Question

A sidewalk in front of Kathy’s house is in the shape of a rectangle four feet wide by $45$feet long. Find the ⓐ perimeter ⓑ area.

Short answer

Part a. The perimeter of the rectangle is $98$feet.

Part b. The area of the rectangle is $180$square feet.

Step-by-step solution

Part (a) Step 1. Given Information

Given that a sidewalk is in the shape of a rectangle four feet wide by $45$feet long.

The objective is to find the perimeter and the area of the rectangle.

Part (a) Step 2. Find the perimeter 

The perimeter of a rectangle is the sum of twice the length and twice the width: $P=2L+2W$

So when the length is localid="1655803616557" $45$feet and width is localid="1655803620164" $4$feet, then the perimeter is given as

$$\begin{gathered} P=2\times 45+2\times 4 \\ P=90+8 \\ P=98 \end{gathered}$$

So the perimeter of the rectangle islocalid="1655803624957" $98$feet.

Part (b) Step 1. Find the area

The area of a rectangle is the length times the width: $A=LW$.

So when the length is $45$feet and width is $4$feet, then the area is given as

$$\begin{gathered} A=45\times 4 \\ A=180 \end{gathered}$$

So the area of the rectangle is $180$square feet.