Question

The length of a rectangle is eight more than twice the width. The perimeter is $64$. Find the length and width.

Short answer

Width is $8$and length is$24$.

Step-by-step solution

Step 1. Given information

Length of rectangle is eight more than twice the width. The perimeter is $64$

Step 2. Finding unknown

Let the width of rectangle is b=x

Therefore the length is $l=2x+8$

According to question,

$$\begin{gathered} 2(l+b)=64 \\ 2(8+2x+x)=64 \\ 2(8+3x)=64 \\ 16+6x=64 \\ 6x=48 \\ x=8=b \end{gathered}$$

Now the length is

$$\begin{gathered} l=2x+8 \\ =2\times 8+8=24 \end{gathered}$$