Question

Find three consecutive even integers whose sum is$-24$

Short answer

The numbers$-10,-8,-6$

Step-by-step solution

Given information

Given sum of three consecutive integers is$-24$

Assume integers as k,k+2,k+4 and calculate

Calculating, we get

$$\begin{gathered} k+k+2+k+4=-24 \\ 3k+6=-24 \\ 3k=-30 \\ k=-10 \end{gathered}$$

The other integers are

$$\begin{gathered} k+2=-10+2 \\ =-8 \\ k+4=-10+4 \\ =-6 \end{gathered}$$

Checking the value

Checking, we get

$$\begin{gathered} -10+(-8)+(-6)=-24 \\ -10-8-6=-24 \\ -24=-24 \end{gathered}$$

So the value is correct