Question

Cindy and Richard leave their dorm in Charleston at the same time. Cindy rides her bicycle north at a speed of $18$miles per hour. Richard rides his bicycle south at a speed of $14$miles per hour. How long will it take them to be $96$miles apart?

Short answer

It will take them$3hours$to be$96miles$apart.

Step-by-step solution

Step 1. Given Information.

Speed of Cindy towards North$=18miles/hr$.

Speed of Richard towards South$=14miles/hr$.

Step 2. Solving the equation

Let the required time be $thours$.

We know, $Dis\tan ce=Speed\times Time$.

Distance traveled by Cindy$=18tmiles$.

Distance traveled by Richard$=14tmiles$.

Therefore,

$$\begin{gathered} 18t+14t=96 \\ 32t=96 \\ t=3 \end{gathered}$$

It will take them$3hours$to be$96miles$apart.