Question

Jason went to the post office and bought both $\backslash (0.41$stamps and $\backslash )0.26$ postcards and spent $\$10.28$. The number of stamps was four more than twice the number of postcards. How many of each did he buy?

Short answer

The number of postcards is $8$and number of stamps is $20$.

Step-by-step solution

Step 1. Given Information  

Total amount $=\$10.28$

Cost of one stamp $=\$0.41$

Cost of one postcard$=\$0.26$

Step 2. Naming the variables   

Let the number of postcards be $x$.

Number of stamps was four more than twice the number of postcards.

Therefore, number of stamps$=4+2x$

Step 3. Creating the table  

The required table is

Step 4. Solving the equation 

Translating into equation we get,

$$\begin{gathered} 0.26x+0.41(4+2x)=10.28 \\ \Rightarrow 0.26x+1.64+0.82x=10.28 \\ \Rightarrow 1.08x=10.28-1.64 \\ \Rightarrow 1.08x=8.64 \\ \Rightarrow x=\frac{8.64}{1.08} \\ \Rightarrow x=8 \\ \therefore (2x+4)=2\left(8\right)+4 \\ \Rightarrow (2x+4)=16+4 \\ \Rightarrow (2x+4)=20 \end{gathered}$$