Question

Joe’s wallet contains \($1$and \)$5$bills worth \($47$. The number of \)$1$bills is five more than the number of $$5$ bills. How many of each bill does he have?

Short answer

The number of$\$1$bills are$12$and$\$5$are$7.$

Step-by-step solution

Step 1. Given Information

Total amount of money$=\$47$

Let he number of $\$5$bills be $x$

Therefore ,

According to the question,

number of $\$1$will be $x+5$

Step 2. Solution of the equation 

Now, According to the question,

$$\begin{gathered} x+5+5x=45 \\ 6x+5=47 \\ 6x=47-5 \\ 6x=42 \\ x=7 \\ Therefore, \\ x+5=x+7=12 \end{gathered}$$