Question

A cash box of \($1$and \)$5$bills is worth \($45$. The number of \)$1$ bills is three more than the number of $$5$ bills. How many of each bill does it contain

Short answer

The number of$\$5$bills are$7and\$1$bills are$10.$

Step-by-step solution

Step 1. Given Information

Total amount of money$=\$45$

Let he number of $\$5$bills be$x$

Therefore ,

According to the question,

number of $\$1$billswill be$x+3$

Step 2. Solution of the equation 

Now, According to the question,

$$\begin{gathered} x+3+5x=45 \\ 6x+3=45 \\ 6x=42 \\ x=7 \\ Therefore, \\ x+3=7+3=10 \end{gathered}$$