Question

Lee has $$1.75$ in dimes and nickels. The number of nickels is $11$ more than the number of dimes. How many of each coin does he have?

Short answer

The number of dimes is $8$and number of nickels is$19$

Step-by-step solution

Step 1. Given Information

Total amount of money$=\$1.75$

Let he number of dimes be $x$

Therefore ,

According to the question,

number of nickels will be$11+x$

Step 2. Solution of the equation 

Value of each dime$0.10$

Value of each nickel is $0.05$

Now, According to the question,

$$\begin{gathered} 0.10x+0.05(x+11)=1.75 \\ 0.10x+0.05x+0.55=1.75 \\ 0.15x+0.55=1.75 \\ 0.15x=1.2 \\ \frac{0.15x}{0.15}=\frac{1.2}{0.15} \\ x=8 \\ 11+x=11+8=19. \end{gathered}$$