Question

In the following exercises, solve:

$16-m^2=0$.

Short answer

The solution for the equation is,

$$\begin{gathered} m=4 \\ m=-4 \end{gathered}$$

Step-by-step solution

Step 1. Given Information.

The equation is,

$16-m^2=0$.

Step 2. Finding the solution.

$16-m^2=0$

Using $(a^2-b^2)=(a+b)(a-b)$,

$$\begin{gathered} \Rightarrow {\left(4\right)}^2-{\left(m\right)}^2=0 \\ \Rightarrow (4+m)(4-m)=0 \\ \Rightarrow 4+m=0 \end{gathered}$$

or, $4-m=0$

$$\begin{gathered} \Rightarrow 4=-m \\ \Rightarrow m=-4 \end{gathered}$$

or,$m=4$