Question

Factor by grouping

$4x^2-16x+3x-12$

Short answer

Factor is:$4x^2-16x+3x-12=(x-4)(4x+3)$

Step-by-step solution

Step 1. Given information

given expression, $4x^2-16x+3x-12$

Step 2. Grouping given expression, 

$4x^2-16x+3x-12=(4x^2-16)(3x-12)$

Step 3. Factor

$$\begin{gathered} (4x^2-16)(3x-12)=4x(x-4)+3(x-4) \\ =(x-4)(4x+3) \end{gathered}$$

Therefore, the factor of the given expression is$(x-4)(4x+3)$