Chapter 9: Problem 6
(Converging hazards) Let \(N(t)=I(\tilde{T} \wedge C \leq t, \tilde{T} \leq C)\) and let \(X\) denote a covariate vector. Consider the situation described in the beginning of Example 9.2.2, where \(N(t)\) has conditional intensity $$ V Y(t) \lambda_{0}(t) \exp \left(X^{T} \beta\right) $$ given \(V\), that is gamma distributed with mean one and variance \(\theta^{-1}\). As usual \(Y(t)=I(t \leq \tilde{T} \wedge C)\) denotes the at risk indicator. (a) Verify that the marginal intensity is $$ Y(t) \frac{\lambda_{0}(t) \exp \left(X^{T} \beta\right)}{1+\theta \exp \left(X^{T} \beta\right) \Lambda_{0}(t)}=Y(t) \alpha_{X}(t) $$ which is a hazard from the Burr distribution. The hazard \(\alpha_{X}(t)\) converges with time, but to zero rather than to an arbitrary baseline hazard. This led Barker \& Henderson (2004) to suggest the following class of hazard models. Partition \(X\) into \(X_{1}\) and \(X_{2}\), and suppose that $$ \alpha X(t)=\frac{\exp \left(X_{1}^{T} \beta_{1}+X_{2}^{T} \beta_{2}\right) \exp \left(\gamma \Lambda_{0}(t)\right)}{1+\exp \left(X_{2}^{T} \beta_{2}\right)\left(\exp \left(\gamma \Lambda_{0}(t)\right)-1\right)} \lambda_{0}(t) $$ where \(\gamma\) is an unknown scalar parameter. (b) Observe the following points. \- At baseline, \(X_{1}=X_{2}=0, \alpha_{X}(t)=\lambda_{0}(t)\); \- If \(\gamma=0\), then the model reduces to the Cox model with covariates \(\left(X_{1}, X_{2}\right)\); if \(\beta_{1}=0\) then the model reduces to the Burr model with covariate \(X_{2}\); \- As \(t\) tends to infinity, \(\alpha_{X}(t)\) converges to \(\exp \left(X_{1}^{T} \beta_{1}\right) \lambda_{0}(t)\), rather than zero. Suppose now that we have \(n\) i.i.d. observations from the generic model given by (9.26). (c) Use a modified likelihood approach similar to the one applied for the proportional odds model in Chapter 8 to construct an estimating equation for \(\phi=\left(\gamma, \beta_{1}, \beta_{2}\right)\), $$ U(\phi)=0 $$ and an estimator of \(\Lambda_{0}(t), \hat{\Lambda}_{0}(t, \hat{\phi})\), where \(\hat{\phi}\) satisfies \(U(\hat{\phi})=0 .\)
Short Answer
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