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Translate each of these nested quantifications into an English statement that expresses a mathematical fact. The domain in each case consists of all real numbers.
\[\begin{array}{l}a)\,\exists x\forall y(xy = y)\\b)\,\forall x\forall y(((x < 0) \wedge (y < 0)) \to (xy > 0))\\c)\,\exists x\exists y((({x^2} > y) \wedge (x < y))\\d)\,\forall x\forall y\exists z(x + y = z)\end{array}\]

Short Answer

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The nested quantifications into English statement that expresses a mathematical fact can be translated.

Step by step solution

01

Translation of the nested quantification for a

a) There exist a real number x as \(\exists x\) and every number y as \(\forall y.\) The product of number x to y and will result in real number y, xy=y. It can be translated as “Subtracting every negative real number from every positive real number will results in a positive real number”.

02

Translation of the nested quantification for b

b) For every real number x and y as \(\forall x\forall y.\) The negative real number x and positive real number y as \((x \ge 0) \wedge (y < 0).\)The product of x and y will result in a positive number as xy>0. It can be translated as “The product of two negative real numbers is always a positive real number”.

03

Translation of the nested quantification for c

c) For every real number x and y as \(\exists x\exists y.\)It exceeds y but x is less than y \((({x^2} > y) \wedge (x < y)) \Rightarrow {x^2}.\) It can be translated as “There exists real numbers x and y such that x2 exceeds y but x is less than y”.

04

Translation of the nested quantification for d

d) For every real number x and y as \(\forall x\forall y.\)There exist z as\(\exists z.\)The sum of x and y is a real number as x+y=z. It can be translated as “There exist a real number which is equal to the sum of every two real numbers”.

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Most popular questions from this chapter

Express these system specifications using the propositions p "The user enters a valid password," q "Access is granted," and r "The user has paid the subscription fee" and logical connectives (including negations).
a) "The user has paid the subscription fee, but does not enter a valid password."
b) "Access is granted whenever the user has paid the subscription fee and enters a valid password."
c) "Access is denied if the user has not paid the subscription fee."
d) "If the user has not entered a valid password but has paid the subscription fee, then access is granted."

A says “We are both knaves” and B says nothing. Exercises 24–31 relate to inhabitants of an island on which there are three kinds of people: knights who always tell the truth, knaves who always lie, and spies (called normals by Sullying [Sm78]) who can either lie or tell the truth. You encounter three people, A, B, and C. You know one of these people is a knight, one is a knave, and one is a spy. Each of the three people knows the type of person each of other two is. For each of these situations, if possible, determine whether there is a unique solution and determine who the knave, knight, and spy are. When there is no unique solution, list all possible solutions or state that there are no solutions

A says “I am the knight,” B says “I am the knight,” and C says “I am the knight.”

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What is the value of x after each of these statements is encountered in a computer program, if x = 1 before the statement is reached?

a) if x+2=3then x=x+1
b) if (x+1=3)OR (2x+2=3)then x=x+1
c) if (2x+3=5)AND (3x+4=7)then x=x+1
d) if (x+1=2)XOR (x+2=3)then x=x+1
e) if x < 2 thenx=x+1

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