Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Use predicates, quantifiers, logical connectives, and mathematical operators to express the statement that every positive integer is the sum of the squares of four integers.

Short Answer

Expert verified

The statement that every positive integer is the sum of the squares of four integers can be expressed using predicates, quantifiers, logical connectives and mathematical operators.

Step by step solution

01

Expression for every positive integers

Take x is a positive integer x>0. The expression for every positive integer is \(\forall x(x > 0).\)Considering there are four integers a, b, c, d can be expressed as \(\exists a\exists b\exists c\exists d.\)The sum of 4 integers square is x and can be represented as \(x = {a^2} + {b^2} + {c^2} + {d^2}.\)

02

Expression for the statement

The sum of the squares of four integers can be a positive integer for all positive values of x. It can be represented as,

\(\forall x(x > 0) \to \exists a\exists b\exists c\exists d(x = {a^2} + {b^2} + {c^2} + {d^2}).\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use truth tables to verify the commutative laws.

(a)pโˆจqโ‰กqโˆจp(b)pโˆงqโ‰กqโˆงp

A says โ€œWe are both knavesโ€ and B says nothing. Exercises 24โ€“31 relate to inhabitants of an island on which there are three kinds of people: knights who always tell the truth, knaves who always lie, and spies (called normals by Smullyan [Sm78]) who can either lie or tell the truth. You encounter three people, A, B, and C. You know one of these people is a knight, one is a knave, and one is a spy. Each of the three people knows the type of person each of other two is. For each of these situations, if possible, determine whether there is a unique solution and determine who the knave, knight, and spy are. When there is no unique solution, list all possible solutions or state that there are no solutions.

A says โ€œI am the knight,โ€ B says โ€œA is telling the truth,โ€ and C says โ€œI am the spy.โ€

The police have three suspects for the murder of Mr. Cooper: Mr. Smith, Mr. Jones, and Mr. Williams. Smith, Jones, and Williams each declare that they did not kill Cooper. Smith also states that Cooper was a friend of Jones and that Williams disliked him. Jones also states that he did not know Cooper and that he was out of town the day Cooper was killed. Williams also states that he saw both Smith and Jones with Cooper the day of the killing and that either Smith or Jones must have killed him. Can you determine who the murderer was if

a) One of the three men is guilty, the two innocent men are telling the truth, but the statements of the guilty man may or may not be true?

b) Innocent men do not lie?

Let p and q be the propositions p : It is below freezing. q : It is snowing. Write these propositions using p and q and logical connectives (including negations).

a) It is below freezing and snowing.
b) It is below freezing but not snowing.
c) It is not below freezing and it is not snowing.
d) It is either snowing or below freezing (or both).
e) If it is below freezing, it is also snowing.
f )Either it is below freezing or it is snowing, but it is not snowing if it is below freezing.
g) That it is below freezing is necessary and sufficient for it to be snowing.

Show that (s*)*=swhen is a compound proposition

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free