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Prove that there exists a pair of consecutive integers such that one of these integers is a perfect square and the other is a perfect cube.

Short Answer

Expert verified

The pair of consecutive integral values 8 and 9, such that 8 is a perfect cube and 9 is a perfect square.

And, the proof is constructive.

Step by step solution

01

Introduction

Consecutive integers are the integers that follow each other in particular order.

02

Proof using constructive method

Consider, 8 and 9 are integral values, and also, they are pair of consecutive integral values.

And,

8=23and9=33

Therefore, the pair of consecutive integral values 8 and 9, such that 8 is a perfect cube and 9 is a perfect square.

Hence, proved and the proof is constructive.

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