Chapter 9: Q58E (page 618)
To determine the equivalence classes under the given relation\(R\).
Short Answer
There is only one equivalence class, as all vertices are related to each other.
Chapter 9: Q58E (page 618)
To determine the equivalence classes under the given relation\(R\).
There is only one equivalence class, as all vertices are related to each other.
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Get started for freeThe 5-tuples in a 5-ary relation represent these attributes of all people in the United States: name, Social Security number, street address, city, state.
a) Determine a primary key for this relation.
b) Under what conditions would (name, street address) be a composite key?
c) Under what conditions would (name, street address, city) be a composite key?
Whether there is a path in the directed graph in Exercise 16 beginning at the first vertex given and ending at the second vertex given.
To find the ordered pairs \((a,b)\) in \({R^2}\;\& \;\;{R^n}\) relation where \(n\) is a positive integer.
In Exercises 25โ27 list all ordered pairs in the partial ordering with the accompanying Hasse diagram.26.
Exercises 34โ37 deal with these relations on the set of real numbers:
\({R_1} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a > b} \right\},\)the โgreater thanโ relation,
\({R_2} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a \ge b} \right\},\)the โgreater than or equal toโ relation,
\({R_3} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a < b} \right\},\)the โless thanโ relation,
\({R_4} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a \le b} \right\},\)the โless than or equal toโ relation,
\({R_5} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a = b} \right\},\)the โequal toโ relation,
\({R_6} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a \ne b} \right\},\)the โunequal toโ relation.
35. Find
(a) \({R_2} \cup {R_4}\).
(b) \({R_3} \cup {R_6}\).
(c) \({R_3} \cap {R_6}\).
(d) \({R_4} \cap {R_6}\).
(e) \({R_3} - {R_6}\).
(f) \({R_6} - {R_3}\).
(g) \({R_2} \oplus {R_6}\).
(h) \({R_3} \oplus {R_5}\).
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