Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

To prove the error in the given proof a theorem.

Short Answer

Expert verified

The error in given proof a theorem is "Take an element \(b \in A\) such that \((a,b) \in R\) ".

Step by step solution

01

 Given

Let \(a \in A\). Take an element \(b \in A\) such that \((a,b) \in R\).

02

The Concept of reflexive relation

Let the relation\(R\)on set\(A\)that is symmetric and transitive. Then\(R\)is reflexive.

03

Determine the relation

Let the relation\(R\)on set\(A\)that is symmetric and transitive. Then\(R\)is reflexive

let\(a \in A\). Take an element\(b \in A\)such that\((a,b) \in R\). because\(R\)is symmetric, we also have\((b,a) \in R\). Now using the transitive property, we can conclude that\((a,a) \in R\). because\((a,b) \in R\)and\((b,a) \in R\).

Consider the statement "relation\(R\)on set\(A\)which is symmetric and transitive. Then\(R\)is reflexive"

If we observe the proof, if the element\(b\)is not exist, then the proof is correct.

Take an element \(b \in A\) such that \((a,b) \in R\). is wrong. Because \(R\) is reflexive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free