Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which of these relations on the set of all people are equivalence relations? Determine the properties of an equivalence relation that the others lack.

Short Answer

Expert verified

\(\{ ({\rm{a}},{\rm{b}})\mid {\rm{a}}\) and \({\rm{b}}\) speak a common language \(\} \) is not an equivalence relation .

Step by step solution

01

Given data

Given data is \(\{ (a,b)\mid a\) and b speak a common language \(\} \).

02

Concept used of equivalence relation

An equivalence relation is a binary relation that is reflexive, symmetric and transitive.

03

Solve for relation

In order to determine if a relation is an equivalent relation, we need to see if said relation is a reflexive, symmetric and transitive.

A relation on a set \({\rm{A}}\) is reflexive if \((a,a) \in R\) for every element \(a \in A\).

A relation on a set \({\rm{A}}\) is symmetric if \((b,a) \in R\) whenever \((a,b) \in A\).

A relation on a set \({\rm{A}}\) is transitive if \((a,b) \in R\) and \((b,c) \in R\) implies \((a,c) \in R\).

It is not transitive since if \(x\) and \(y\) speak a common language, say Spanish; and \(y\) and \(z\) speak another common language, say English; it doesn't mean that \(x\) and \(z\) speak a common language .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free