Question

Which projection mapping is used to delete the first, second, and fourth components of a 6-tuple?

Short answer

The resultant answer is \({P_{3,\;5,\;6}}\).

Step-by-step solution

Given data

6-tuple is given.

Concept of sets

The concept of set is a very basic one.

It is simple; yet, it suffices as the basis on which all abstract notions in mathematics can be built.\(A\)set is determined by its elements.

If\(A\)is a set, write\(x \in A\)to say that\(x\)is an element of\(A\).

Simplify the expression

Consider the set of 6-tuple \((A,B,C,D,E,F)\).

If we apply the \({P_{3,\;5,\;6}}\) then we will get the set \((C,E,F)\), which does not contain first, second and fourth component.

Therefore, we apply the \({P_{3,\;5,\;6}}\) to delete first, second and fourth component.