Question

Find$210\mathrm{div}17\mathrm{and}210\mathrm{mod}17$

Short answer

$$\begin{gathered} 210div17=12 \\ 210mod17=6 \end{gathered}$$

Step-by-step solution

Step 1

Division algorithm- Let abe an integer and da positive integer. Then there are unique integers $\mathrm{q}\mathrm{and}\mathrm{r}\mathrm{with}0\le \mathrm{r}<\mathrm{d}$such that .

qis called the quotient and is called the remainder.

$$\begin{gathered} \mathrm{q}=\mathrm{a}\mathrm{div}\mathrm{d} \\ \mathrm{r}=\mathrm{a}\mathrm{mod}\mathrm{d} \end{gathered}$$

Step 2

SOLUTION

$210=204+6=12\cdot 17+6$

Since $0\le 6<17$

$$\begin{gathered} 210\mathrm{div}17=12 \\ 210\mathrm{mod}17=6 \end{gathered}$$