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Show that if \(A\) is a regular set, then so is \(\bar A\).

Short Answer

Expert verified

The give A is regular then \(\bar A\) is also regular

Step by step solution

01

Definition 

For any Regular Expression r that represents Language \(L(r)\), there is a Finite Automata that accepts the same language.

02

Proving that A is regular

You invoke the power of Kleene's theorem here. If A is a regular set, then there is a deterministic finite automaton that accepts A. If you take the same machine but make all the final states nonfinal and all the nonfinal states final, then the result will accept precisely \(\bar A\). Therefore \(\bar A\) is regular.

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Most popular questions from this chapter

Determine whether each of these strings is recognized by the deterministic finite-state automaton in Figure 1.

a)010b) 1101 c) 1111110d) 010101010

a) Construct a phrase-structure grammar that generates all signed decimal numbers, consisting of a sign, either + or โˆ’; a nonnegative integer; and a decimal fraction that is either the empty string or a decimal point followed by a positive integer, where initial zeros in an integer are allowed.

b) Give the Backusโ€“Naur form of this grammar.

c) Construct a derivation tree for โˆ’31.4 in this grammar.

Find a phrase-structure grammar for each of these languages.

a) the set consisting of the bit strings 10, 01, and 101.

b) the set of bit strings that start with 00 and end with one or more 1s.

c) the set of bit strings consisting of an even number of 1s followed by a final 0.

d) the set of bit strings that have neither two consecutive 0s nor two consecutive 1s.

use top-down parsing to determine whether each of the following strings belongs to the language generated by the grammar in Example 12.

\(\begin{array}{*{20}{l}}{{\bf{a) baba}}}\\{{\bf{b) abab}}}\\{{\bf{c) cbaba}}}\\{{\bf{d) bbbcba}}}\end{array}\)

Describe how productions for a grammar in extended Backusโ€“Naur form can be translated into a set of productions for the grammar in Backusโ€“Naur form.

This is the Backusโ€“Naur form that describes the syntax of expressions in postfix (or reverse Polish) notation.

\(\begin{array}{c}\left\langle {{\bf{expression}}} \right\rangle {\bf{ :: = }}\left\langle {{\bf{term}}} \right\rangle {\bf{|}}\left\langle {{\bf{term}}} \right\rangle \left\langle {{\bf{term}}} \right\rangle \left\langle {{\bf{addOperator}}} \right\rangle \\{\bf{ }}\left\langle {{\bf{addOperator}}} \right\rangle {\bf{:: = + | - }}\\\left\langle {{\bf{term}}} \right\rangle {\bf{:: = }}\left\langle {{\bf{factor}}} \right\rangle {\bf{|}}\left\langle {{\bf{factor}}} \right\rangle \left\langle {{\bf{factor}}} \right\rangle \left\langle {{\bf{mulOperator}}} \right\rangle {\bf{ }}\\\left\langle {{\bf{mulOperator}}} \right\rangle {\bf{:: = *|/}}\\\left\langle {{\bf{factor}}} \right\rangle {\bf{:: = }}\left\langle {{\bf{identifier}}} \right\rangle {\bf{|}}\left\langle {{\bf{expression }}} \right\rangle \\\left\langle {{\bf{identifier}}} \right\rangle {\bf{:: = a }}\left| {{\bf{ b }}} \right|...{\bf{| z}}\end{array}\)

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