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A stable assignment, defined in the preamble to Exercise 60 in Section 3.1, is called optimal for suitors if no stable assignment exists in which a suitor is paired with a suitee whom this suitor prefers to the person to whom this suitor is paired in this stable assignment. Use strong induction to show that the deferred acceptance algorithm produces a stable assignment that is optimal for suitors.

Short Answer

Expert verified

The deferred acceptance algorithm produces a stable assignment that is optimal for suitors. The statement holds true forn=1 number of suitors and it also holds true for number of suitors. The statement also holds truen=k+1 for suitors of n=1,2,...,k.

Step by step solution

01

Significance of the strong induction

The strong induction is mainly described as a proof which is related to the simple induction. The strong induction is mainly used for proving a particular theorem.

02

Determination of the deferred acceptance algorithm

Let P(n)is described as a statement which states that “deferred acceptance algorithm produces a stable assignment that is optimal for suitors, when there are number of suitees and number of suitors”.

In the basic step where n=1, as there are only suitee and suitors, the suitor has been assigned by the stable assignment to the particular suitee and the particular assignment is also optimal for a particular suitor. Hence, P(1)holds true.

In the inductive step, let the series P(1),P(2),....,P(k)holds true, then it is to be considered that P(k+1)is also true. Let, the number of suitees and suitors are k+1respectively. If the k+1suitors are being divided into two different groups such asQ and p, then the algorithm of deferred acceptance mainly produces a stable assignment which is mainly optimal for the and also suitors which states thatP(1),P(2),....,P(k) holds true. Hence,P(k+1) holds true.

Thus, the deferred acceptance algorithm produces a stable assignment that is optimal for suitors. The statement holds true forn=1 number of suitors and it also holds true forn=k+1 number of suitors. The statement also holds true for suitors of n=1,2,...,k.

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