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Devise an algorithm for finding the second shortest path between two vertices in a simple connected weighted graph.

Short Answer

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It found that the second case may be that it doesn’t exist.

Step by step solution

01

Step 1:Finding the second shortest path

In order to find the simple shortest path first,

It needs to find out the shortest path between\(a\)to\(z\)(By the use of Dijkstra’s algorithm).

Then consider for each of the edges e in the path of one by one,

Then let omit e from the graph and again try to find a shortest path between a to z in the graph that remains after omission.

It even ensures that whether no such path exists.

02

Conclusion

Therefore, the second shortest path from \(a\)to\(z\)is a path of minimum length among all the paths so found and the second case may be that it doesn’t exist.

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Most popular questions from this chapter

Suppose that\({\bf{G}}\)is a connected multi graph with\({\bf{2k}}\)vertices of odd degree. Show that there exist\({\bf{k}}\)sub graphs that have\({\bf{G}}\)as their union, where each of these subgraphs has an Euler path and where no two of these subgraphs have an edge in common. (Hint: Add\({\bf{k}}\)edges to the graph connecting pairs of vertices of odd degree and use an Euler circuit in this larger graph.)

\(\)

A dominating set of vertices in a simple graph is a set of vertices such that every other vertex is adjacent to at least one vertex of this set. A dominating set with the least number of vertices is called a minimum dominating set. Find a minimum dominating set for the given graph.

Show that if \({\bf{G}}\) is a simple graph with at least 11 vertices, then either \({\bf{G}}\)or\({\bf{\bar G}}\), the complement of \({\bf{G}}\), is non-planar.

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