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Question:In a super lottery, a player wins a fortune if they choose the eight numbers selected by a computer from the positive integers not exceeding 100. What is the probability that a player wins this super lottery?

Short Answer

Expert verified

Answer

The probability that a person wins the grand prize by picking 7 numbers that are among the 11 numbers selected at random by a computer, provided a player selects 7 numbers out of the first 80 positive integers is P(E)=5.37×10-12.

Step by step solution

01

 Given  

The positive integers not exceeding 100.

02

The Concept of Probability

IfSrepresents the sample space andE represents the event. Then the probability of occurrence of favourable event is given by the formula as below:

P(E)=n(E)n(S)

03

Determine the probability

As per the problem we have been asked to find the probability that a person wins the grand prize by picking 8 numbers selected by a computer from the positive integers not exceeding 100.

If Srepresents the sample space and Erepresents the event. Then the probability of occurrence of favourable event is given by the formula as below:

P(E)=n(E)n(S).

So, the number of possible ways of select 8 numbers out of the first 100 positive integers isn(s)=100C8.

Total number of ways that the 8 numbers selected by a player to be in 8 numbers selected by computer at random isn(E)=8C8.

There will be only one set of positive integers for which lottery can be drawn.

The probability that a person wins the grand prize by picking 8 numbers selected by a computer from the positive integers not exceeding 100 is as follows:

P(E)=C88C8100P(E)=1186087894300P(E)=5.37×10-12

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Most popular questions from this chapter

Question: What is the probability that a fair die comes up six when it is rolled?

Question 2. To determine the smallest number of people you need to choose at random so that the probability that at least one of them has a birthday today exceeds12 .

Question: Prove Theorem \(2\), the extended form of Bayes’ theorem. That is, suppose that \(E\) is an event from a sample space \(S\) and that \({F_1},{F_2},...,{F_n}\) are mutually exclusive events such that \(\bigcup\nolimits_{i = 1}^n {{F_i} = S} \). Assume that \(p\left( E \right) \ne 0\) and \(p\left( {{F_i}} \right) \ne 0\) for \(i = 1,2,...,n\). Show that

\(p\left( {{F_j}\left| E \right.} \right) = \frac{{p\left( {E\left| {{F_j}} \right.} \right)p\left( {{F_j}} \right)}}{{\sum\nolimits_{i = 1}^n {p\left( {E\left| {{F_i}} \right.} \right)p\left( {{F_i}} \right)} }}\)

(Hint: use the fact that \(E = \bigcup\nolimits_{i = 1}^n {\left( {E \cap {F_i}} \right)} \).)

Question 2. To determine

  1. What probability distribution for birthday’s should be used to reflect how often February29occurs?
  2. What is the probability that in a group ofnpeople at least two have the same birthday using the probability distribution froma?

Question:Ramesh can get to work in three different ways: by bicycle, by car, or by bus. Because of commuter traffic, there is a\({\bf{50}}\% \)chance that he will be late when he drives his car. When he takes the bus, which uses a special lane reserved for buses, there is a\({\bf{20}}\% \)chance that he will be late. The probability that he is late when he rides his bicycle is only\({\bf{5}}\% \). Ramesh arrives late one day. His boss wants to estimate the probability that he drove his car to work that day.

a) Suppose the boss assumes that there is a\({\bf{1}}/{\bf{3}}\)chance that Ramesh takes each of the three ways he can get to work. What estimate for the probability that Ramesh drove his car does the boss obtain from Bayes’ theorem under this assumption?

b) Suppose the boss knows that Ramesh drives\(3{\bf{0}}\% \)of the time, takes the bus only\({\bf{10}}\)% of the time, and takes his bicycle\({\bf{60}}\% \)of the time. What estimate for the probability that Ramesh drove his car does the boss obtain from Bayes’ theorem using this information?

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