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How many ways are there to seat six boys and eight girls in a row of chairs so that no two boys are seated next to each other?

Short Answer

Expert verified

The number of different ways to seat six boys and eight girls in a row of chairs such that no two boys are seated next to each other is \({\rm{20321280}}\)ways.

Step by step solution

01

Assume the seats.

To find the ways to seat six boys and eight girls.So the number of different ways to seat six boys and eight girls in a row of chairs such that no two boys are seated next two each other, first we will arrange eight girls in \(P(8,8) = 8! = 40320\) ways such that between each pair of a girl will allow to seat a boy.

02

 Arrangements

Now we can have\({\rm{9}}\)positions for six boys, this can be arranged in

\(P(9,6) = 9 \times 8 \times 7 = 504\)

Therefore, the required number of different ways to seat six boys and eight girls in a row of chairs such that no two boys are seated next to each other is \({\rm{20321280}}\) ways.

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