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Design a circuit for a light fixture controlled by four switches, where flipping one of the switches turns the light on when it is off and turns it off when it is on.

Short Answer

Expert verified

The result is\(\overline x yzw + x\overline y zw + xy\overline z w + xyz\overline w \).

Step by step solution

01

Defining of gates

There are three types of gates.

It is also called NOT gate.

02

Construct a circuit

A circuit that implements four inputs requires. Let the inputs are x, y, z, w. And flipping one of the switches turns the light on when it is off and turns it off when it is on.

The outputs is\(\overline x yzw + x\overline y zw + xy\overline z w + xyz\overline w \).

Therefore, the outputs are\(\overline {\rm{x}} {\rm{yzw + x}}\overline {\rm{y}} {\rm{zw + xy}}\overline {\rm{z}} {\rm{w + xyz}}\overline {\rm{w}} \).

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Most popular questions from this chapter

Use a \({\bf{K}}\)-map to find a minimal expansion as a Boolean sum of Boolean products of each of these functions in the variables \({\bf{w, x, y}}\) and \({\bf{z}}\).

\(\begin{array}{l}{\bf{a) wxyz + wx\bar yz + wx\bar y\bar z + w\bar xy\bar z + w\bar x\bar yz}}\\{\bf{b) wxy\bar z + wx\bar yz + w\bar xyz + \bar wx\bar yz + \bar w\bar xy\bar z + \bar w\bar x\bar yz}}\\{\bf{c) wxyz + wxy\bar z + wx\bar yz + w\bar x\bar yz + w\bar x\bar y\bar z + \bar wx\bar yz + \bar w\bar xy\bar z + \bar w\bar x\bar yz}}\\{\bf{d) wxyz + wxy\bar z + wx\bar yz + w\bar xyz + w\bar xy\bar z + \bar wxyz + \bar w\bar xyz + \bar w\bar xy\bar z + \bar w\bar x\bar yz}}\end{array}\)

Show that if \({\bf{F}}\) and \({\bf{G}}\) are Boolean functions represented by Boolean expressions in \({\bf{n}}\) variables and \({\bf{F = G}}\), then \({{\bf{F}}^{\bf{d}}}{\bf{ = }}{{\bf{G}}^{\bf{d}}}\), where \({{\bf{F}}^{\bf{d}}}\) and \({{\bf{G}}^{\bf{d}}}\) are the Boolean functions represented by the duals of the Boolean expressions representing \({\bf{F}}\) and \({\bf{G}}\), respectively. (Hint: Use the result of Exercise \(29\).)

Express each of the Boolean functions in Exercise 3 using the operator \( \downarrow \).

Show that if \(F\) and \(G\) are Boolean functions of degree \(n\), then

\(\begin{array}{l}a)F \le F{\bf{ + }}G\\b)FG \le F\end{array}\)

Find the sum-of-products expansion of the Boolean function\({\bf{F}}\left( {{\bf{w, x, y, z}}} \right)\) that has the value 1 if and only if an odd number of w, x, y, and z have the value 1.

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