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Chapter 12: Q2E (page 827)

In Exercises 1–5 find the output of the given circuit.

Short Answer

Expert verified

The output of the circuit is (x +y).

Step by step solution

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01

Defining of gates

There are three types of gates.

It is also called NOT gate.

02

Find the output

The first and second gates are NOT gate. So output is negative. The third gate is AND gate. AND fourth gate is NOT gate.

Therefore, the output circuit is (x +y).

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Most popular questions from this chapter

Show that if \({\bf{F, G}}\), and \({\bf{H}}\) are Boolean functions of degree \({\bf{n}}\), then \({\bf{F + G}} \le {\bf{H}}\) if and only if \({\bf{F}} \le {\bf{H}}\) and \({\bf{G}} \le {\bf{H}}\).

Find a minimal sum-of-products expansion, given the \(K{\bf{ - }}\)map shown with don't care conditions indicated with\(d\)’s.

Simplify these expressions.

\(\begin{array}{l}{\bf{a) x}} \oplus {\bf{0}}\\{\bf{b) x}} \oplus {\bf{1}}\\{\bf{c) x}} \oplus {\bf{x}}\\{\bf{d) x}} \oplus {\bf{\bar x}}\end{array}\)

Show that \({\bf{x}} \oplus {\bf{y = y}} \oplus {\bf{x}}\).

How many cells in a \({\bf{K}}\)-map for Boolean functions with six variables are needed to represent \({{\bf{x}}_{\bf{1}}}{\bf{,}}{{\bf{\bar x}}_{\bf{1}}}{{\bf{x}}_{\bf{6}}}{\bf{, }}{{\bf{\bar x}}_{\bf{1}}}{{\bf{x}}_{\bf{2}}}{{\bf{\bar x}}_{\bf{6}}}{\bf{,}}{{\bf{x}}_{\bf{2}}}{{\bf{x}}_{\bf{3}}}{{\bf{x}}_{\bf{4}}}{{\bf{x}}_{\bf{5}}}\), and \({{\bf{x}}_{\bf{1}}}{{\bf{\bar x}}_{\bf{2}}}{{\bf{x}}_{\bf{4}}}{{\bf{\bar x}}_{\bf{5}}}\), respectively\({\bf{?}}\)
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