Chapter 12: Q26E (page 818)
Show that \({\bf{x}} \oplus {\bf{y = y}} \oplus {\bf{x}}\).
Short Answer
The given \(x \oplus y = y \oplus x\)is proved.
Chapter 12: Q26E (page 818)
Show that \({\bf{x}} \oplus {\bf{y = y}} \oplus {\bf{x}}\).
The given \(x \oplus y = y \oplus x\)is proved.
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\(\begin{array}{l}{\bf{a) x}} \oplus {\bf{0}}\\{\bf{b) x}} \oplus {\bf{1}}\\{\bf{c) x}} \oplus {\bf{x}}\\{\bf{d) x}} \oplus {\bf{\bar x}}\end{array}\)
Show that \({\bf{x}} \odot {\bf{y = xy + \bar x\bar y}}\).
\(a)\)Explain how \(K{\bf{ - }}\)maps can be used to simplify sum-of-products expansions in three Boolean variables.
\(b)\)Use a \(K{\bf{ - }}\)map to simplify the sum-of-products expansion \({\bf{xyz + x\bar yz + x\bar y\bar z + \bar xyz + \bar x\bar y\bar z}}\).
Is it always true that \((x \odot y) \odot z{\bf{ = }}x \odot (y \odot z)\)\(?\)
Show that if \(F\) and \(G\) are Boolean functions of degree \(n\), then
\(\begin{array}{l}a)F \le F{\bf{ + }}G\\b)FG \le F\end{array}\)
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