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How many different Boolean functions are there of degree \(7\)\({\bf{?}}\)

Short Answer

Expert verified

The Boolean function of degree 7 will be

\(340,282,336,920,938,463,463,374,607,431,768,211,456\)

Step by step solution

01

Definition

Product rule: If one event can occur in m ways AND a second event can occur in n ways, then the number of ways that the two events can occur in sequence is then \(m \times n\)

02

Using the Boolean product

A Boolean function of degree n is a function from \({{\bf{B}}_{\bf{n}}}{\bf{ = }}\left\{ {\left( {{{\bf{x}}_{\bf{1}}}{\bf{,}}{{\bf{x}}_{\bf{2}}}{\bf{, \ldots ,}}{{\bf{x}}_{\bf{n}}}} \right)\mid {{\bf{x}}_{\bf{i}}} \in {\bf{B}}} \right\}\) to \({\bf{B = }}\left\{ {{\bf{0,1}}} \right\}\), \(n = 7\). A Boolean function of degree 7 consists of 7 Boolean variables. Since each Boolean variable can take on 2 values (0 or 1, you can determine the number of 7 tuples for the 7 Boolean variables by using the product rule:\(\underbrace {{\bf{2 \times 2 \times \ldots \times 2}}}_{{\bf{7 times }}}{\bf{ = }}{{\bf{2}}^{\bf{7}}}{\bf{ = 128}}\) 7- tuples. A Boolean function is the assignment of 0 or 1 to each of the 128 7-tuples.

Thus, by the product rule, you can then determine the number of Boolean functions of

degree 7: \(\underbrace {{\bf{2 \times 2 \times \ldots \times 2}}}_{{{\bf{2}}^{\bf{7}}}{\bf{ = 128 times }}}{\bf{ = }}\)

\({2^{{2^7}}} = {2^{128}} = 340,282,336,920,938,463,463,374,607,431,768,211,456\).

Therefore, the Boolean function of degree 7 will be

\(340,282,336,920,938,463,463,374,607,431,768,211,456\)

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Most popular questions from this chapter

Find a minimal sum-of-products expansion, given the \(K{\bf{ - }}\)map shown with don't care conditions indicated with\(d\)โ€™s.

Use a \({\bf{K}}\)-map to find a minimal expansion as a Boolean sum of Boolean products of each of these functions in the variables \({\bf{w, x, y}}\) and \({\bf{z}}\).

\(\begin{array}{l}{\bf{a) wxyz + wx\bar yz + wx\bar y\bar z + w\bar xy\bar z + w\bar x\bar yz}}\\{\bf{b) wxy\bar z + wx\bar yz + w\bar xyz + \bar wx\bar yz + \bar w\bar xy\bar z + \bar w\bar x\bar yz}}\\{\bf{c) wxyz + wxy\bar z + wx\bar yz + w\bar x\bar yz + w\bar x\bar y\bar z + \bar wx\bar yz + \bar w\bar xy\bar z + \bar w\bar x\bar yz}}\\{\bf{d) wxyz + wxy\bar z + wx\bar yz + w\bar xyz + w\bar xy\bar z + \bar wxyz + \bar w\bar xyz + \bar w\bar xy\bar z + \bar w\bar x\bar yz}}\end{array}\)

Which of these functions are self-dual?

\(\begin{array}{l}\left. {\bf{a}} \right)\;{\bf{F}}\left( {{\bf{x,y}}} \right) = x\\\left. {\bf{b}} \right)\;{\bf{F}}\left( {{\bf{x,y}}} \right) = {\bf{xy + \bar x\bar y}}\\\left. {\bf{c}} \right)\;{\bf{F}}\left( {{\bf{x,y}}} \right) = {\bf{x + y}}\\\left. {\bf{d}} \right)\;{\bf{F}}\left( {{\bf{x,y}}} \right) = {\bf{xy + \bar xy}}\end{array}\)

Find a Boolean product of the Boolean variables x, y,and z, or their complements, that has the value 1 if and only if

a)x=y=0, z=1

b)x=0, y=1, z=0

c)x=0, y=z=1

d)x=y=z=0

Construct a circuit for a full subtractor using AND gates, OR gates, and inverters. A full subtractor has two bits and a borrow as input, and produces as output a difference bit and a borrow.

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