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Show that if f1xand f2(x)are functions from the set of positive integers to the set of real numbers androle="math" localid="1668678872142" f1(x)isΘ(g1(x))andf2(x)isΘ(g2(x)), then(f1f2)(x)isrole="math" localid="1668678882006" Θ(g1(x)) .

Short Answer

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In the question, it is given that f1(x)and f2(x)are the functions such that f1(x)andf2(x)both areΘ(g(x)) . And we have to prove that f1f2(x)isΘg1g2(x).

Step by step solution

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01

Step 1:

For f1(x)isΘg1(x), applying the definition of Big-theta Notation

f1(x)a1g1(x)ifx>b1f1(x)a2g1(x)ifx>b2

Where,a1,a2,b1andb2 are constants.

Forf2(x)isΘg2(x) is , applying the definition of Big-theta Notation

f2(x)a3g2(x)ifx>b3f2(x)a4g2(x)ifx>b4

Wherea3,a4,b3andb4 are constants

02

Step 2:

We can take, b = maxb1,b2,b3,b4

Multiplying f1(x)a1g1(x)andf2(x)a3g2(x)

f1(x)f2(x)a1g1(x)a3g2(x)

We get,f1f2(x)a1a3g1g2(x)

Hence, f1f2(x)isOg1g2(x)withb=maxb1,b2,b3,b4anda=a1a3

Multiplyingf1(x)a2g1(x)andf2(x)a4g2(x)

f1(x)f2(x)a2g1(x)a4g2(x)

We get, f1f2(x)a2a4g1g2(x)

So, f1f2(x)isΩg1g2(x)withb=maxb1,b2,b3,b4anda=a2a4

03

Step 3:

By using f1f2(x)isOg1g2(x)f1f2(x)isΩg1g2(x)

Hence, by using the definition of Big-theta Notation, we can conclude that is f1f2(x)isΘg1g2(x) .

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