Question

Devise an algorithm that finds the first term of a sequence of positive integers that is less than the immediately preceding term of the sequence.

Short answer

An algorithm for determining the first term of a sequence of positive integers that is less than the immediately preceding term of the sequence.

procedureposition ($a_1,a_2,..,a_n:$ list of positive integers)

j = 2

position := 0

while$j\le n$ and position = 0

will show the position of the first term of a sequence of positive integers that is less than the immediately preceding term of the sequence

Step-by-step solution

Write the steps required to follow to determine Algorithm.

First set j equals to 2 and position equals to 2 .

Then use while loop to examine given list and condition for while loop is$j\le n$ and$position=0$ .

In while compare$a_j$ and$a_{j-1}$ using the if loop with condition$a_j<a_{j-1}$and when if loop becomes true, return then position as position = j and when if loop becomes false then increase k by 1 . After the completion of if loop increase j by 1 .

Here the position is our required answer.

Determine the steps of the algorithm.

By using the above conditions, the algorithm findsthe first term of a sequence of positive integers that is less than the immediately preceding term of the sequence.

procedureposition ($a_1,a_2,...,a_n$ list of positive integers)

j = 2

position : = 0

while $j\le n$and position = 0