Question

Describe an algorithm that will count the number of 1s in a bit string by examining each bit of the string to determine whether it is a 1 bit.

Short answer

An algorithm that will count the number ofin a bit string by examining each bit of the string to determine whether it is a , is given as below:

Procedure$one\left(y_1,y_2,...,y_m:stringwithn\ge 1\right)$

count := 0

For$i:=1$ to m

If$y_k=1$ then

$count:=count+1$

return

Algorithm will return count , which is total number of 1s in the given string.

Step-by-step solution

Steps Algorithm follows

Steps that algorithm has to follow are:

1. Initialize count as 0 . This variable will give the count of all 1s in the string.
2. We will use if statement to detect if current bit is 1 , if the condition is true, then increment count by .
3. Use for loop to check every bit in the string 1 .
4. Finally, Algorithm will return total number of 1s in the string.

Step 2:

The algorithm based on above conditions given as below:

Procedure$one\left(y_1,y_2,...,y_m:stringwithn\ge 1\right)$

$count:=0$

For$i:=1$ to m

If$y_k=1$ then

$count:=count+1$

returncount