Chapter 6: Problem 6
Show that \(B\) is the inverse of \(A\). \(A=\left[\begin{array}{rrr}-1 & 0 & 2 \\ 1 & -2 & 0 \\ 1 & 0 & 3\end{array}\right], B=\frac{1}{10}\left[\begin{array}{rrr}-6 & 0 & 4 \\ -3 & -5 & 2 \\ 2 & 0 & 2\end{array}\right]\)
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