Chapter 5: Problem 35
Solve the system of equations. $$\left\\{\begin{aligned} x &+3 w=4 \\ 2 y-z-w &=0 \\ 3 y-2 w &=1 \\ 2 x-y+4 z &=5 \end{aligned}\right.$$
Short Answer
Expert verified
The solution to the system of equations is \( x = 1, y = 7/6, z = 4/3, w = 1 \)
Step by step solution
01
Solve the first equation for x
By manipulating the first equation, it can be rewritten in terms of \( x \). This gives: \( x = 4 - 3w \)
02
Substitute x into the fourth equation
Substitute \( x = 4 - 3w \) into the fourth equation, this will help to simplify the equation system: \( 2(4 - 3w) - y + 4z = 5 \). Simplify this equation to get: \( 8 - 6w - y + 4z = 5 \), or equivalently, \( -6w - y + 4z = -3 \).
03
Combine the second and the new fourth equation
We can add the second equation \( 2y - z - w = 0 \) and the new fourth equation \( -6w - y + 4z = -3 \). The result is: \( -7w + 3z = -3 \)
04
Solve the new equation for z
By manipulating the new equation, it can be rewritten in terms of \( z \). This gives: \( z = (7w - 3)/3 \)
05
Substitute z into the second equation
Substitute \( z = (7w - 3)/3 \) into the second equation. This will give a new equation in terms of only w and y. The new equation is: \( 2y - (7w - 3)/3 - w = 0 \). Simplify it to get: \( 2y - 10w/3 + 1 = 0 \), or equivalently, \( y = (10w - 3)/6 \)
06
Substitute this y into the third equation
Substitute \( y = (10w - 3)/6 \) into the third equation: \( 3(10w - 3)/6 - 2w = 1 \) . Simplify this equation to get the value of \( w \), which is \( w = 1 \)
07
Back substitute w into the y, z, x equations
Back substitute \( w = 1 \) into the equations for \( y, z, x \) to find their values as well. Simplifying gives: \( y = (10*1 - 3)/6 = 7/6, z = (7*1 - 3)/3 = 4/3, x = 4 - 3*1 = 1 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Equations
Linear equations form the building blocks of systems of equations. They are algebraic equations where each term is either a constant or the product of a constant and a single variable. The general form of a linear equation in one variable is expressed as:
\[ ax + b = 0 \]where \(a\) and \(b\) are constants and \(x\) is the variable.
In our exercise, we have multiple such equations, meaning we need to find the solution for several variables.
Some characteristics of linear equations include:
\[ ax + b = 0 \]where \(a\) and \(b\) are constants and \(x\) is the variable.
In our exercise, we have multiple such equations, meaning we need to find the solution for several variables.
Some characteristics of linear equations include:
- They graph as straight lines when plotted on a coordinate plane.
- Each equation has a degree of 1, meaning the highest power of the variable is 1.
- They can represent various real-world scenarios, like calculating costs or converting temperatures.
Substitution Method
The substitution method is a crucial concept used to solve systems of linear equations. This technique involves solving one of the equations for one variable and then substituting that expression into the other equations.
This process simplifies the system and reduces the number of variables, making it easier to solve.
Here's how you can execute the substitution method effectively:
This process simplifies the system and reduces the number of variables, making it easier to solve.
Here's how you can execute the substitution method effectively:
- Choose one equation from the system and solve for one variable. For example, solve \(x + 3w = 4\) to get \(x = 4 - 3w\).
- Substitute this expression into the other equations. Replace \(x\) in other equations with \(4 - 3w\).
- Simplify the system using the new equations, and continue substituting until all variables are solved.
Simultaneous Equations
Simultaneous equations refer to a set of equations that are solved together since they share common variables. The objective is to find values for the variables that satisfy all the equations in the system simultaneously.
In our exercise, we deal with equations like:
In our exercise, we deal with equations like:
- \(x + 3w = 4\)
- \(2y - z - w = 0\)
- \(3y - 2w = 1\)
- \(2x - y + 4z = 5\)
- Elimination Method: Involves adding or subtracting equations to eliminate a variable, simplifying the process of finding solutions.
- Graphical Method: Entails graphing each equation and finding the intersection point that represents the solution.