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Solve the system by the method of substitution. Then use the graph to confirm your solution. $$ \left\\{\begin{array}{l} y=-x^{2}+1 \\ y=x^{2}-1 \end{array}\right. $$

Short Answer

Expert verified
The solution to the system of equations \(y=-x^{2}+1\) and \(y=x^{2}-1\) are the ordered pairs (-1,0) and (1,0).

Step by step solution

01

Substitution

Substitute \(x^{2}-1\) for \(y\) in the first equation to obtain: \(-x^{2}+1=x^{2}-1\).
02

Simplify the equation

Add \(x^{2}\) to both sides and add 1 to both sides to get: \(2x^{2}=2\). Divide both sides by 2 to solve for \(x\): \(x^{2}=1\). Taking the square root of both sides reveals the two potential values for \(x\), which are \(x=-1\) and \(x=1\).
03

Substitute \(x\) into one of the original equations

Substitute the values for \(x\) into the first equation, one at a time, to find the corresponding values of \(y\). When \(x=-1\), \(y=-(-1)^{2}+1=-1+1=0\). When \(x=1\), \(y=-(1)^{2}+1=-1+1=0\). Thus, the solutions are (-1,0) and (1,0).
04

Graph the equations to confirm solution

Graph each equation on the same coordinate plane. The equation \(y=-x^2+1\) is a downward-opening parabola with its vertex at (0,1). The equation \(y=x^2-1\) is an upward-opening parabola with its vertex at (0,-1). Both equations intersect at the points (-1, 0) and (1,0), thus confirming the solutions obtained algebraically.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The Substitution Method is a technique used to solve systems of equations by replacing a variable with an expression from another equation. In this method, we first solve one of the equations for one variable. Then, we substitute this expression into the other equation to find the value of the remaining variable.

In this exercise, we had the system:
  • \( y = -x^{2} + 1 \)
  • \( y = x^{2} - 1 \)
By substituting \( y = x^{2} - 1 \) into the equation \( y = -x^{2} + 1 \), we set up the equation \( -x^{2} + 1 = x^{2} - 1 \). This method allows us to transform two separate equations into one, making it easier to find the values of the variables involved.

This technique is quite powerful as it reduces the complexity of solving systems by handling one equation at a time.
Graphing
Graphing is a visual method to solve equations where we draw the equations on a coordinate plane and observe where they intersect. Each intersection point represents a solution to the system of equations.

In the given example, we graph the equations:
  • \( y = -x^{2} + 1 \)
  • \( y = x^{2} - 1 \)
The graphs of these equations are parabolas, and they intersect at points \((-1, 0)\) and \((1, 0)\). These intersection points confirm the solutions found through substitution. Graphing is a useful tool because it gives a clear, visual representation of the solutions.

It also aids in understanding the relationships between equations and the nature of their graphs. When equations are complex, graphing can provide insight that algebraic manipulation alone might miss.
Parabolas
Parabolas are a special type of curve on a graph that are represented by quadratic equations like \( y = ax^{2} + bx + c \). They have a distinct U-shape, which can either open upwards or downwards depending on the sign of the coefficient of \( x^2 \).

In our system of equations, both equations form parabolas:
  • \( y = -x^{2} + 1 \) forms a downward-opening parabola.
  • \( y = x^{2} - 1 \) forms an upward-opening parabola.
The vertex of the parabola is the point where it turns, often representing the maximum or minimum point of the curve.

Understanding the properties of parabolas is important in graphing because it helps predict the shape and direction of the curve. Parabolas are common in many fields, including physics and engineering, hence recognizing their properties and intersections is crucial for real-world applications.
Solving Quadratics
Solving quadratic equations is a process of finding the values of the variable that satisfy the quadratic expression. These values are often found using methods such as factoring, completing the square, or using the quadratic formula.

In our solved system, the equation \( 2x^{2} = 2 \) simplifies to \( x^{2} = 1 \). Solving this by taking the square root gives us solutions \( x = -1 \) and \( x = 1 \). It's important to remember that a quadratic equation can have up to two real solutions, which correspond to the points where the parabola intersects the x-axis.

Grasping the fundamentals of solving quadratics is key, as it enables us to handle more complex equations and systems. Quadratics frequently appear in various mathematical problems, making mastering them a valuable skill.

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Most popular questions from this chapter

Optimal Profit A manufacturer produces two models of elliptical cross-training exercise machines. The times for assembling, finishing, and packaging model \(\mathrm{A}\) are 3 hours, 3 hours, and \(0.8\) hour, respectively. The times for model B are 4 hours, \(2.5\) hours, and \(0.4\) hour. The total times available for assembling, finishing, and packaging are 6000 hours, 4200 hours, and 950 hours, respectively. The profits per unit are \(\$ 300\) for model \(A\) and $$\$ 375$$ for model \(B\). What is the optimal production level for each model? What is the optimal profit?

Revenues Per Share The revenues per share (in dollars) for Panera Bread Company for the years 2002 to 2006 are shown in the table. In the table, \(x\) represents the year, with \(x=0\) corresponding to \(2003 .\) (Source: Panera Bread Company) $$ \begin{array}{|c|c|} \hline \text { Year, } x & \text { Revenues per share } \\ \hline-1 & 9.47 \\ \hline 0 & 11.85 \\ \hline 1 & 15.72 \\ \hline 2 & 20.49 \\ \hline 3 & 26.11 \\ \hline \end{array} $$ (a) Find the least squares regression parabola \(y=a x^{2}+b x+c\) for the data by solving the following system. \(\left\\{\begin{array}{r}5 c+5 b+15 a=83.64 \\\ 5 c+15 b+35 a=125.56 \\ 15 c+35 b+99 a=342.14\end{array}\right.\) (b) Use the regression feature of a graphing utility to find a quadratic model for the data. Compare the quadratic model with the model found in part (a). (c) Use either model to predict the revenues per share in 2008 and \(2009 .\)

Graph the solution set of the system of inequalities. $$\left\\{\begin{aligned}-3 x+2 y &<6 \\ x+4 y &<-2 \\ 2 x+y &<3 \end{aligned}\right.$$

Computers The sales \(y\) (in billions of dollars) for Dell Inc. from 1996 to 2005 can be approximated by the linear model \(y=5.07 t-22.4, \quad 6 \leq t \leq 15\) where \(t\) represents the year, with \(t=6\) corresponding to 1996\. (Source: Dell Inc.) (a) The total sales during this ten-year period can be approximated by finding the area of the trapezoid represented by the following system. \(\left\\{\begin{array}{l}y \leq 5.07 t-22.4 \\ y \geq 0 \\ t \geq 5.5 \\ t \leq 15.5\end{array}\right.\) Graph this region using a graphing utility. (b) Use the formula for the area of a trapezoid to approximate the total sales.

Graphical Reasoning Two concentric circles have radii \(x\) and \(y\), where \(y>x .\) The area between the circles must be at least 10 square units. (a) Find a system of inequalities describing the constraints on the circles. (b) Use a graphing utility to graph the system of inequalities in part (a). Graph the line \(y=x\) in the same viewing window. (c) Identify the graph of the line in relation to the boundary of the inequality. Explain its meaning in the context of the problem.

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