Chapter 4: Problem 94
Solve for \(y\) in terms of \(x\).\(\log _{10}(y-4)+\log _{10} x=3 \log _{10} x\)
Short Answer
Expert verified
The solution to the problem is \(y = x^2 + 4\).
Step by step solution
01
Combine Logarithm Rules
First, we use the logarithm properties to simplify the equation. According to the log properties, if we have \(\log_b(m) + \log_b(n)\), we can combine these two logs into \(\log_b(mn)\). So, the equation becomes: \(\log _{10}[(y-4)x] = 3\log _{10} x\)
02
Apply Power Rule to Logarithm
Then, apply the power rule of logarithms, which states that \(a \log_b(m) = \log_b(m^a)\). So, the equation becomes: \(\log _{10}[(y-4)x] = \log _{10}(x^3)\)
03
Cancel out Logarithm
Logarithms with the same base cancel out, so if we have \(\log _{10}(a) = \log _{10}(b)\) it means that \(a = b\). Thus, we have '((y-4)x = x^3)'.
04
Solve for y
Finally, solve for \(y\), we have \(y = \frac{x^3}{x} + 4 = x^2 + 4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithm Properties
Understanding the properties of logarithms can make solving logarithmic equations much easier. One of the essential properties used in solving the given problem is the property of the sum of logarithms. When you have \(\log_b(m) + \log_b(n)\), you can combine these into a single logarithm as \(\log_b(mn)\). This is called the "product rule" for logarithms. It’s useful for simplifying expressions that add two or more logarithms with the same base.
In the original problem, we used this property to combine \(\log_{10}(y-4) + \log_{10}x\) into \(\log_{10}[(y-4)x]\). Recognizing opportunities to use logarithmic properties can significantly streamline the process of manipulating and simplifying equations.
Another vital property is when you encounter a logarithmic equation like \(\log_{10}(a) = \log_{10}(b)\). This property states that if two logs with the same base are equal, then the values inside them are equal as well, i.e., \(a = b\). This allows us to drop the logarithms entirely and solve a simpler algebraic equation instead.
In the original problem, we used this property to combine \(\log_{10}(y-4) + \log_{10}x\) into \(\log_{10}[(y-4)x]\). Recognizing opportunities to use logarithmic properties can significantly streamline the process of manipulating and simplifying equations.
Another vital property is when you encounter a logarithmic equation like \(\log_{10}(a) = \log_{10}(b)\). This property states that if two logs with the same base are equal, then the values inside them are equal as well, i.e., \(a = b\). This allows us to drop the logarithms entirely and solve a simpler algebraic equation instead.
Power Rule
The power rule of logarithms is another crucial tool that aids in solving logarithmic expressions. According to this rule, multiplying a logarithm by a real number can be rewritten as raising the argument of the logarithm to the power of that real number.
In mathematical terms, the power rule can be expressed as \(a \log_b(m) = \log_b(m^a)\).
This rule is particularly handy when you encounter an equation like \(3\log_{10}x\). You can rewrite this as \(\log_{10}(x^3)\).
The power rule simplifies equations, making them easier to solve by allowing you to express exponential growth within the logarithm’s argument. In our example, applying this rule transformed the right side of the equation from \(3\log_{10} x\) to \(\log_{10}(x^3)\), making it easier to equate with the left side.
In mathematical terms, the power rule can be expressed as \(a \log_b(m) = \log_b(m^a)\).
This rule is particularly handy when you encounter an equation like \(3\log_{10}x\). You can rewrite this as \(\log_{10}(x^3)\).
The power rule simplifies equations, making them easier to solve by allowing you to express exponential growth within the logarithm’s argument. In our example, applying this rule transformed the right side of the equation from \(3\log_{10} x\) to \(\log_{10}(x^3)\), making it easier to equate with the left side.
Solving Equations
Solving logarithmic equations involves several strategic steps. After simplifying the given logarithmic expressions using properties like the product rule and power rule, the next phase is to equate the simplified expressions and solve the algebraic equation.
In our example, after simplification, we were left with the equation \(\log_{10}[(y-4)x] = \log_{10}(x^3)\). At this point, because both sides have the same logarithmic base, \(\log_{10}\), we can directly equate their arguments: \((y-4)x = x^3\).
Now, you're left with a simpler equation to solve: \(y-4 = x^2\), after dividing both sides by \(x\), assuming \(x eq 0\). Finally, adding 4 to both sides gives the solution for \(y\), which is \(y = x^2 + 4\).
The steps involve reducing the logarithmic equation to a basic algebraic form and then using standard algebraic methods to isolate and solve for the variable. Always check the domain of the solution to ensure that it is valid within the context of the original logarithmic equation.
In our example, after simplification, we were left with the equation \(\log_{10}[(y-4)x] = \log_{10}(x^3)\). At this point, because both sides have the same logarithmic base, \(\log_{10}\), we can directly equate their arguments: \((y-4)x = x^3\).
Now, you're left with a simpler equation to solve: \(y-4 = x^2\), after dividing both sides by \(x\), assuming \(x eq 0\). Finally, adding 4 to both sides gives the solution for \(y\), which is \(y = x^2 + 4\).
The steps involve reducing the logarithmic equation to a basic algebraic form and then using standard algebraic methods to isolate and solve for the variable. Always check the domain of the solution to ensure that it is valid within the context of the original logarithmic equation.