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Solve the logarithmic equation algebraically. Approximate the result to three decimal places.lnx+2=1

Short Answer

Expert verified
The approximate solution for 'x' is 5.389.

Step by step solution

01

Simplify the radical expression

First, note that x+2 can be rewritten in exponential form as (x+2)1/2. So our equation becomes ln(x+2)1/2=1.
02

Convert logarithmic form to exponential form

The equation ln(x+2)1/2=1 can be rewritten in exponential form using the property that if lnb=a, then b=ea. So our equation becomes (x+2)1/2=e1.
03

Solve for 'x'

Square both sides to eliminate the square root on the left side: (x+2)=(e1)2 which simplifies to x+2=e2. Then, subtract 2 from both sides to solve for 'x': x=e22.
04

Approximate the result

Use a calculator to compute e22 and round to three decimal places: x5.389.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Logarithmic Equations
To solve logarithmic equations like lnx+2=1, one must understand the relationship between logarithms and exponents. A logarithm is essentially an exponent itself; it represents the power to which a base number must be raised to produce a given number. Here's a step-by-step breakdown on how to solve the given logarithmic equation:

First, translate the radical expression into exponential form, which simplifies the process. Knowing that the square root is the same as raising to the power of 1/2, we restate the equation as ln(x+2)1/2=1. This simplifies the radical and makes it easier to manipulate algebraically.

Next, by using the conversion between logarithmic and exponential form, we can now rewrite the equation as e1, since the natural logarithm ln is implicitly with base e, the Euler's number. This is a critical step because it converts a logarithm to an exponent, which then allows for straightforward algebraic operations. After this, we solve for x by squaring both sides, which removes the fractional exponent, and then isolating x.

Finally, with the value of e known, a calculator can be used to approximate the result to three decimal places. For students, practicing these steps on a variety of problems deepens understanding and hones the skill of manipulating and solving logarithmic equations.
Converting Logarithms to Exponential Form
The ability to convert logarithms to exponential form is crucial for solving logarithmic equations. The conversion leverages the fact that a logarithm answers the question: 'To what power must we raise the base to get a certain number?' Mathematically, if logba=c, then bc=a.

This property underscores the intimate relationship between logarithms and exponents; they are essentially inverse operations. For the natural logarithm lna=b, we convert to exponential form by raising Euler's number e to the power of b, making eb=a.

Understanding this concept and translating between these two forms enable students to easily handle more complex equations involving logarithms. It's a transformation that often simplifies the problem, moving it from logarithmic terrain into the more familiar territory of polynomial equations.
Properties of Logarithms
Logarithms carry distinctive properties that are particularly useful in solving equations. One fundamental property is the Power Rule, which allows the exponent on the logarithm's argument to be moved to the front as a multiplier, expressed as logb(ac)=clogb(a).

In our example, the natural logarithm's argument is raised by 1/2, and so it could be brought in front as a multiplier, which is helpful in certain contexts.

Apart from the Power Rule, there is the Product Rule that turns the multiplication of two numbers within a logarithm into the addition of two logarithms, and the Quotient Rule which turns division into subtraction. Each of these properties fundamentally allows the transformation of a logarithmic statement into a form that is easier to compute or compare.

Understanding and utilizing the properties of logarithms not only simplifies complex algebraic expressions but also enables one to grasp the deeper concepts at play when it comes to dealing with logarithmic relationships in mathematics.
Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. They are written in the form f(x)=bx, where b is a positive real number not equal to 1. The variable x appears as the exponent, which means that the value of the function grows exponentially with x.

These functions are characterized by their rapid growth or decay and are commonly used to model situations where something increases at a constant rate percentage-wise, such as in the cases of population growth, compound interest, and radioactive decay.

The natural exponential function, with the base as Euler's number e, is particularly important due to its unique properties and its appearance in various areas of science, finance, and mathematics. It's the function's innate rapid growth characteristic that allows it to describe many natural phenomena so accurately. Recognizing how exponential functions operate and how they can be manipulated mathematically is a key skill for students who are delving into higher-level mathematics and its applications.

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Most popular questions from this chapter

Automobiles are designed with crumple zones that help protect their occupants in crashes. The crumple zones allow the occupants to move short distances when the automobiles come to abrupt stops. The greater the distance moved, the fewer g's the crash victims experience. (One g is equal to the acceleration due to gravity. For very short periods of time, humans have withstood as much as 40 g's.) In crash tests with vehicles moving at 90 kilometers per hour, analysts measured the numbers of g's experienced during deceleration by crash dummies that were permitted to move x meters during impact. The data are shown in the table. x0.20.40.60.81.0g 's 15880534032A model for these data is given by y=3.00+11.88lnx+36.94x where y is the number of g's. (a) Complete the table using the model.x0.20.40.60.81.0y(b) Use a graphing utility to graph the data points and the model in the same viewing window. How do they compare? (c) Use the model to estimate the least distance traveled during impact for which the passenger does not experience more than 30 g 's. (d) Do you think it is practical to lower the number of g's experienced during impact to fewer than 23 ? Explain your reasoning.

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