Question

Reasoning A classmate claims that the following is true: \(\ln (x+y)=\ln x+\ln y=\ln x y\) Discuss how you would use a graphing utility to demonstrate that this claim is not true. Describe how to demonstrate the actual property of logarithms that is hidden in this faulty claim.

Short answer

The claim \(\ln (x+y)=\ln x+\ln y\) is incorrect, as shown by comparing the graphs of these functions on a graphing utility. The correct logarithmic property hidden in this false claim is \(\ln(xy)= \ln x + \ln y\), proven by the coincidence of the respective function graphs.

Step-by-step solution

Graph the Functions

Using a graphing calculator or other graphing utility, enter three different functions: \(y_1 = \ln(x+y)\), \(y_2=\ln x + \ln y\), and \(y_3=\ln (xy)\). Choose suitable values for x and y, ensuring that none of them are negative (as the natural logarithm \(\ln x\) is undefined for negative values).

Visual Comparison

Examine the graphs produced – \(y_1\), \(y_2\), and \(y_3\). Particularly, compare the graphs of \(y_1=\ln(x+y)\) and \(y_2=\ln x + \ln y\). These two graphs will not coincide with each other, indicating that \(\ln(x+y)\) and \(\ln x + \ln y\) are, in fact, not equivalent.

Comparison with the Correct Property

Now, compare the graphs of \(y_2=\ln x + \ln y\) and \(y_3=\ln (xy)\). It should become evident that these two equate, demonstrating the verified property of logarithms, \(\ln(xy)= \ln x + \ln y\).

Final Conclusion

To conclude, the initial claim that \(\ln (x+y)=\ln x+\ln y\) is not true, and this has been visually shown using a graphing utility. The correct property, which was hidden in the incorrect claim, is \(\ln(xy)= \ln x + \ln y\), and the graphing utility confirmed it.

Key concepts

Natural Logarithm Laws

Understanding the laws governing natural logarithms is essential for students delving into deeper concepts of algebra and calculus. Natural logarithms, denoted as \(\ln(x)\), have specific rules that facilitate simplifying complex expressions.

One foundational law is:\[\ln(xy) = \ln(x) + \ln(y)\], which states that the logarithm of a product is equal to the sum of the logarithms of the factors. Contrarily, the false statement \(\ln(x+y) = \ln(x) + \ln(y)\) is not in accordance with the laws of logarithms and leads to misconceptions. Grasping these laws not only prevents errors but also streamlines problem-solving by converting multiplication into addition, which is typically simpler to manage.

Graphing Calculator Utility

Graphing calculators serve as invaluable tools for visualizing mathematical concepts and verifying the accuracy of equations. Their utility is particularly relevant when exploring properties of logarithms. To illustrate an incorrect claim like \(\ln(x+y) = \ln(x) + \ln(y)\), a student can input separate functions into a graphing calculator and visually analyze the disparity between the resultant graphs.

Why Graphing Calculators Are Helpful

With a graphing calculator, students can quickly compare the shapes and intersection points of different functions, such as \(y_1 = \ln(x+y)\), \(y_2 = \ln(x) + \ln(y)\), and \(y_3 = \ln(xy)\), to confirm or refute purported logarithmic properties. This tactile experience reinforces the abstract algebraic concepts, making them more tangible and approachable.

Logarithm Equivalence

Logarithm equivalence refers to situations where two logarithmic expressions represent the same value. In the context of natural logarithms, the correct equivalence \(\ln(xy) = \ln(x) + \ln(y)\) stems from the fundamental properties of logarithms. Conversely, \(\ln(x+y)\) and \(\ln(x) + \ln(y)\) are not equivalent, as addition inside the logarithm does not split into separate logarithms of addends. Understanding the nuances of logarithm equivalence is crucial to correctly applying transformations and solving logarithmic equations.

Recognizing Equivalent Expressions

Students must learn to recognize valid logarithmic equivalences, like the product-to-sum conversion, while also spotting and correcting misconceptions that can lead to incorrect simplifications or solutions in algebraic problems.

Misconceptions in Algebra

Misconceptions in algebra are often the result of overgeneralizing rules or neglecting the unique properties of algebraic operations, as seen with the misunderstanding of logarithm laws. A common error is the assumption that operations inside the logarithm can be distributed into separate logarithms, leading to incorrect statements such as \(\ln(x+y) = \ln(x) + \ln(y)\).

Importance of Correct Understanding

Correcting these misconceptions is essential, as they can compromise the foundation of a student's mathematical knowledge, causing persistent errors in calculations and reasoning. Educators should emphasize the correct principles and provide ample opportunities for students to practice and visualize the concepts, using tools such as graphing calculators to reinforce their understanding and prevent common algebraic mistakes.