Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Solve the quadratic equation. $$4 x^{2}+16 x+15=0$$

Short Answer

Expert verified
The solutions to the equation are \(x = -1.5\) and \(x = -2.5\).

Step by step solution

01

Identify coefficients

First identify the coefficients a, b, and c in the given equation. In this equation, \(4x^2+16x+15 = 0\), a = 4, b = 16, and c = 15.
02

Applying the Quadratic Formula

Next, substitute the values of a, b, and c into the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\). Using this formula givesx = \frac{-16 \pm \sqrt{16^2-4(4)(15)}}{2*4}= \frac{-16 \pm \sqrt{256-240}}{8}= \frac{-16 \pm \sqrt{16}}{8}.
03

Simplifying the result

Lastly, simplify this further to find the roots. This gives x1 = \frac{-16 + 4}{8} = -1.5 and x2 = \frac{-16 - 4}{8} = -2.5. This means the solutions of the equation are x = -1.5 and x = -2.5.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Quadratic Formula
The quadratic formula is a fundamental tool in algebra for finding the roots of quadratic equations, which are equations of the form \(ax^2 + bx + c = 0\). When faced with an equation like \(4x^2 + 16x + 15 = 0\), the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\) allows you to find the values of \(x\) that make the equation true.

To use it, you'll need to identify the coefficients – \(a\), \(b\), and \(c\) – which are the numerical factors before \(x^2\), \(x\), and the constant term, respectively. Here, \(a=4\), \(b=16\), and \(c=15\). After plugging these into the formula, simplifying is crucial. Simplifying the square root of the discriminant \(\sqrt{b^2-4ac}\) and the fractions can often reveal the roots in their simplest form.

Understanding and applying the quadratic formula is key to solving many algebraic problems, and while it may seem daunting at first, with practice it can become a straightforward and efficient method.
Factoring Quadratic Equations
Factoring is another method for solving quadratic equations, where you express the quadratic in the form \(ax^2 + bx + c\) as a product of binomials. For the equation \(4x^2 + 16x + 15 = 0\), one might look for two numbers that multiply to \(ac\) and add up to \(b\). However, in this case, factoring by inspection might be challenging due to the larger coefficients, so other methods such as the quadratic formula might be easier.

When factoring is straightforward, it's an efficient method as it can often be done mentally with practice and helps to understand the nature of the quadratic equation more deeply. Factoring can reveal the zeros of the function, or the x-intercepts of the graph, providing a clear visual representation of the solutions.
Coefficients of Quadratic Equations
In a quadratic equation, the coefficients are the numbers in front of the terms with variables. They are essential because they determine the shape and position of the parabola when the quadratic equation is graphed. The standard form of a quadratic equation is \(ax^2 + bx + c = 0\), with \(a\), \(b\), and \(c\) as the coefficients.

In our example \(4x^2 + 16x + 15 = 0\), \(4\) is the coefficient of \(x^2\), which affects the width and the direction of the parabola. A positive \(a\) means the parabola opens upward, while a negative \(a\) would open it downward. The coefficient \(16\) of \(x\) influences the position of the vertex along the x-axis, and \(15\) is the constant term that moves the parabola up or down the y-axis.

By understanding how these coefficients interact with the graph of the equation, one can predict the number and nature of the roots without even solving it. If \(a\) and \(c\) have the same sign, the quadratic will have no real roots. If they have opposite signs, there are two real roots, as in the example given.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Algebraic and Graphical Approaches In Exercises \(31-46\), find all real zeros of the function algebraically. Then use a graphing utility to confirm your results. $$g(t)=t^{5}-6 t^{3}+9 t$$

Population The immigrant population \(P\) (in millions) living in the United States at the beginning of each decade from 1900 to 2000 is shown in the table. (Source: Center of Immigration Studies) $$ \begin{aligned} &\begin{array}{|l|c|c|c|c|} \hline \text { Year } & 1900 & 1910 & 1920 & 1930 \\ \hline \text { Population, } P & 10.3 & 13.5 & 13.9 & 14.2 \\ \hline \end{array}\\\ &\begin{array}{|l|l|l|l|l|} \hline \text { Year } & 1940 & 1950 & 1960 & 1970 \\ \hline \text { Population, } P & 11.6 & 10.3 & 9.7 & 9.6 \\ \hline \end{array}\\\ &\begin{array}{|l|l|l|l|} \hline \text { Year } & 1980 & 1990 & 2000 \\ \hline \text { Population, } P & 14.1 & 19.8 & 30.0 \\ \hline \end{array} \end{aligned} $$ (a) Use a graphing utility to create a scatter plot of the data. Let \(t=0\) correspond to 1900 . (b) Use what you know about end behavior and the scatter plot from part (a) to predict the sign of the leading coefficient of a cubic model for \(P\). (c) Use the regression feature of a graphing utility to find a cubic model for \(P\). Does your model agree with your answer from part (b)? (d) Use a graphing utility to graph the model from part (c). Use the graph to predict the year in which the immigrant population will be about 45 million. Is your prediction reasonable?

Regression Problem Let \(x\) be the number of units (in tens of thousands) that a computer company produces and let \(p(x)\) be the profit (in hundreds of thousands of dollars). The table shows the profits for different levels of production. $$ \begin{aligned} &\begin{array}{|l|l|l|l|l|l|} \hline \text { Units, } x & 2 & 4 & 6 & 8 & 10 \\ \hline \text { Profit, } p(x) & 270.5 & 307.8 & 320.1 & 329.2 & 325.0 \\ \hline \end{array}\\\ &\begin{array}{|l|l|l|l|l|l|} \hline \text { Units, } x & 12 & 14 & 16 & 18 & 20 \\ \hline \text { Profit, } p(x) & 311.2 & 287.8 & 254.8 & 212.2 & 160.0 \\ \hline \end{array} \end{aligned} $$ (a) Use a graphing utility to create a scatter plot of the data. (b) Use the regression feature of a graphing utility to find a quadratic model for \(p(x)\). (c) Use a graphing utility to graph your model for \(p(x)\) with the scatter plot of the data. (d) Find the vertex of the graph of the model from part (c). Interpret its meaning in the context of the problem. (e) With these data and this model, the profit begins to decrease. Discuss how it is possible for production to increase and profit to decrease.

Use the graph of \(y=x^{4}\) to sketch the graph of the function. $$f(x)=3-x^{4}$$

Determine (a) the maximum number of turning points of the graph of the function and (b) the maximum number of real zeros of the function. $$f(x)=x^{2}-4 x+1$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free