Question

Write the quotient in standard form. $$\frac{4}{(1-2 i)^{3}}$$

Short answer

The quotient in standard form is: Write down your final answer here.

Step-by-step solution

Calculate the Cube

To begin, calculate the cubic value of \(1-2i\). Let's represent \(1-2i\) as \(z\). Then \((1 - 2i)^3 = z^3\). Perform the multiplication to get the value.

Simplify Using the Conjugate

Next, to simplify the fraction, identify the conjugate of \(1-2i\), which is \(1+2i\) and multiply both the numerator and denominator by it. This gets rids of the imaginary part from the denominator.

Simplify the complex number

Recognize the structure as a complex number in the form of \(a + bi\). Then express it in standard form.

Key concepts

Imaginary Units

Complex numbers consist of two components: a real part and an imaginary part. The imaginary unit, denoted by the symbol \(i\), is the foundational building block of complex numbers. It is defined by the property \(i^2 = -1\). This unique definition of \(i\) allows for the arithmetic of square roots of negative numbers, a task that is impossible in the set of real numbers alone.

When working with expressions involving \(i\), it's essential to remember some key powers of \(i\):

• \(i^0 = 1\)
• \(i^1 = i\)
• \(i^2 = -1\)
• \(i^3 = -i\)
• \(i^4 = 1\) (which starts the cycle over)

These cyclical properties of \(i\) make it possible to simplify expressions containing powers of \(i\). In complex arithmetic, the presence of \(i\) in a denominator often requires rationalization, a process intimately linked with its imaginary nature.

Conjugate

The conjugate of a complex number is a key concept used to simplify complex expressions. If a complex number is given in the form \(a + bi\), its conjugate is \(a - bi\). The primary utility of the conjugate lies in its ability to eliminate the imaginary part of a denominator when multiplying complex fractions.

For example, in the original exercise, the denominator \((1-2i)\) has the conjugate \((1+2i)\). When multiplying any complex number by its conjugate, the result is always a real number because:

• \((a+bi)(a-bi) = a^2 - (bi)^2\), which simplifies to \(a^2 + b^2\) as the \(-i^2\) term equals \(+1\).

Using the conjugate to simplify expressions like the one in the given exercise makes the task of expressing a quotient in standard complex form straightforward and methodical.

Standard Form

Standard form for a complex number is the format \(a + bi\), where \(a\) and \(b\) are real numbers. This format distinctly separates the real and imaginary components of a complex number, providing clear visibility into both parts.

To convert a complex quotient into standard form, one typically has to:

• Multiply the numerator and the denominator by the conjugate of the denominator to remove any imaginary component.
• Simplify the resulting expression such that both the real and imaginary parts are clear.

For instance, to express the quotient \(\frac{4}{(1-2i)^3}\) in standard form, one must first ascertain the cube of \((1-2i)\), then apply the conjugate to rationalize the denominator. The result is a complex number expressed as \(a + bi\), a standard form showing both real and imaginary parts cleanly and separately, making it easier to interpret and utilize in further calculations.