The quadratic formula is a reliable method to find the zeros of any quadratic equation. Quadratic equations are those of the form \(ax^2 + bx + c = 0\). The quadratic formula offers a precise manner to solve them:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
This formula automatically applies to our function \(f(x) = \frac{1}{3}x^2 + \frac{1}{3}x - \frac{2}{3}\). In this instance, \(a\), \(b\), and \(c\) have values of \(\frac{1}{3}\), \(\frac{1}{3}\), and \(-\frac{2}{3}\) respectively.
Plugging these into the formula, we solve for \(x\):
- \(x = \frac{-\frac{1}{3} \pm \sqrt{(\frac{1}{3})^2 - 4(\frac{1}{3})(-\frac{2}{3})}}{2 \cdot \frac{1}{3}}\)
- After simplifying, we find \(x = -1\) or \(x = 2\)
This dual result matches our real zeros from the previous calculation. The quadratic formula not only gives precise solutions but also reveals whether the roots are real or complex. In our situation, a positive discriminant \(b^2 - 4ac\) shows that the zeros are real.