Question

Determine whether the equation represents \(y\) as a function of \(x\). \(x^{2}+y^{2}=4\)

Short answer

The equation \(x^{2}+y^{2}=4\) doesn't represent y as a function of x because each value of x has two corresponding values of y, violating the definition of a function that every input must have exactly one output.

Step-by-step solution

Solve for y

Rewrite the given equation, \(x^{2}+y^{2}=4\), solving for y. Subtract \(x^{2}\) from both sides to get \(y^{2} = 4 - x^{2}\). To solve for y, take the square root of both sides, which yields \(y = \pm \sqrt{4 - x^{2}}\).

Test for a function

We check whether every x value has a unique y value. Here, we see that each value in the domain of x, which is \(-2 \leq x \leq 2\), has two corresponding y values, one from the positive root and one from the negative root. This means the equation doesn't represent a function of x under the specific definition of function.

Key concepts

Equations

Equations serve as a fundamental component in mathematics, acting as statements of equality between two expressions. In the realm of functions, an equation can describe a relationship between input values, usually denoted as \(x\), and output values, referred to as \(y\). For example, the equation \(x^2 + y^2 = 4\) represents a circle centered at the origin with a radius of 2 in the Cartesian plane.

The process of analyzing such an equation often involves manipulating it to uncover meaningful insights about the relationships it portrays. For instance, by solving an equation for \(y\) in terms of \(x\), we can better understand if we have a valid function, which is a specific type of relationship determined by equations.

Equations like \(x^2 + y^2 = 4\) do not immediately indicate the nature of the relationship until you perform operations like solving for one variable. This reveals whether the equation serves multiple purposes, used both in defining functions and investigating properties of more complex mathematical concepts.

Domain and Range

Understanding the domain and range of a function is crucial to analyzing its complete behavior. The **domain** of a function represents all possible input values, known as \(x\) values, for which the function is defined.

In the equation \(x^2 + y^2 = 4\), if we solve for \(y\), we get \(y = \pm \sqrt{4 - x^2}\). Here, the domain is not every real number, but the specific interval where \(4 - x^2\) is non-negative. Thus, the domain is \(-2\leq x \leq 2\).

The **range** consists of all possible output values (\(y\) values) the function can produce. Since for each \(x\) within the domain, \(y\) can be both positive and negative, you have a symmetric range about the x-axis. This reflects in \(y\)'s values going from 0 to 2 and 0 to -2. Understanding how the range reverses with different inputs is key in determining the nature of the function.

Function Definition

The definition of a function is rooted in the idea of mapping each element from the domain (set of inputs) to exactly one element in the range (set of outputs). This one-to-one correspondence is essential for calling a relation a function.

When investigating equations like \(x^2 + y^2 = 4\), we need to determine if it fits this function criterion. Solving for \(y\) reveals that for each \(x\) within the domain, there are two potential \(y\) values – one positive, one negative – because of the \(\pm\) in the solution \(y = \pm\sqrt{4 - x^2}\).

This means the equation \(x^2 + y^2 = 4\) does not define a function of \(x\) since one input \(x\) can yield more than one output \(y\). For a relation to qualify as a function, it must pass the "vertical line test," which means any vertical line drawn over the graph should intersect it at no more than one point.