Chapter 12: Problem 63
Use a symbolic integration utility to evaluate the integral. $$ \int_{0}^{5} x^{4}\left(25-x^{2}\right)^{3 / 2} d x $$
Short Answer
Expert verified
The definite integral of the given function from 0 to 5 is 25.
Step by step solution
01
Identify Approach- Substitution
Given function can be altered to a form that allows easier computation via substitution. Let us replace \(25 - x^2\) with \(u\), so that the derivative \(-2x\) can be eliminated in the process of substitution.
02
Perform the Substitution
Let's substitute \(u = 25 - x^2\), which gives \(du = -2x \, dx\). Rearranging for \(dx\) gives \(dx = -du/(2x)\). The new limits for \(u\) are \(25 - 0^2 = 25\) (lower limit) and \(25 - 5^2 = 0\) (upper limit). Substitute these values into the integral, which gives \(-\frac{1}{2} \int_{25}^{0} u^{3/2} du\).
03
Evaluate the Integral
This integral can be evaluated using the power rule, which states that the integral of \(u^n\) is \(u^{n+1} /(n+1)\). Applying this gives \(-\frac{1}{2} [(2/5) u^{5/2}]_{25}^{0}\).
04
Substitute u Back
We have to substitute back the u-values to x: \(-\frac{1}{5} [(25 - x^2)^{5/2} ]_{0}^{5}\).
05
Evaluate Definite Integral
The last step is to substitute the limits of the integral into the integral. This gives \(-\frac{1}{5} [(0) - (25^{5/2})] = \frac{125}{5} = 25\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method in Integration
The substitution method is a powerful technique in calculus, particularly useful when dealing with integrals of more complex functions. It works much like the reverse of the chain rule for derivatives. The idea is to transform the complicated function into a simpler one, which we can integrate easily, by substituting a part of the original function with a new variable.
Choosing the Substitution
In our example, noticing that the function inside the integral, \(25 - x^2\), raised to a power complicates the integral. By introducing the substitution \(u = 25 - x^2\), we simplify the integrand to a form where the integral becomes straightforward to compute.Dealing with the Differentiation Variable
A crucial step in substitution is to express \(dx\) in terms of \(du\). We calculate the derivative of \(u\) with respect to \(x\) to find \(du\), and then solve for \(dx\). This allows us to rewrite the entire integral in terms of \(u\) and \(du\).Adjusting the Limits
If we're performing a definite integral, we also need to change the limits of integration to reflect our new variable \(u\). This avoids having to substitute back to \(x\) after finding the indefinite integral and simplifies the solution process.Definite Integral and Its Evaluation
A definite integral has both a start and an end point, called the limits of integration, and it represents the area under the curve of a function on a specified interval. To solve a definite integral, we find the indefinite integral first, which is the antiderivative of the function, and then apply the limits.
Application of the Substitution
After substitution and changing the limits accordingly, we have a new integral \(\int_{25}^{0} u^{3/2} du\) with limits that correspond to the new variable \(u\). Even though the limits seem reversed, which would normally mean the integral would evaluate to a negative area, we note that there's also a negative sign from the substitution. These two negatives will cancel each other out in the final evaluation.Final Evaluation
The final step in evaluating a definite integral is to plug in the upper limit into the antiderivative, subtract the value obtained by plugging in the lower limit, and interpret the result. In this case, when we substituted back to \(x\) and applied the limits, we found the area represented by the original integral to be 25.Power Rule for Integration
The power rule for integration is a basic rule that helps us integrate functions of the form \(x^n\). It states that the integral of \(x^n\) with respect to \(x\) is \(\frac{1}{n+1} x^{n+1}\), plus a constant of integration when dealing with an indefinite integral.