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Evaluate the definite integral. $$ \int_{2}^{4} \frac{x^{2}}{(3 x-5)} d x $$

Short Answer

Expert verified
The exact value of the integral is \( 44 \).

Step by step solution

01

Set the Value of U

Set the substitution variable, \( u = 3x - 5 \), which simplifies the denominator.
02

Find the value of dx

Differentiate \( u = 3x - 5 \) with respect to \( x \) to find \( du/dx = 3 \), from which we get \( dx = du/3 \).
03

Substitute in the Integral

Substitute \( u \) and \( dx \) in the integral to get a new integral: \( \int_{1}^{3} \frac{(u + 5)^2}{u} * (du/3) \).
04

Simplify the Integral

Simplify the integrand to get \( \int_{1}^{3} (u/3 + 5)^2 du \).
05

Evaluate the Integral

Evaluate the integral to obtain \( \frac{1}{9}u^3 + 5u^2 + 25u |_{1}^{3} \).
06

Substitute U Back

Substitute \( u = 3x - 5 \) back in to get \( \frac{1}{9}(3x - 5)^3 + 5x^2 + 25x \) and evaluate this from 2 to 4.
07

Final Answer

Calculate the final answer by using the fundamental theorem of calculus: \( F(4) - F(2) \) where \( F(x) = \frac{1}{9}(3x - 5)^3 + 5x^2 + 25x \).

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