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Decide whether the integral is improper. Explain your reasoning. $$ \int_{1}^{\infty} x^{2} d x $$

Short Answer

Expert verified
The integral \(\int_{1}^{\infty} x^{2} dx\) is an improper integral since the interval of integration is infinite.

Step by step solution

01

Identify the limits of integration and the function to be integrated

The given integral is \(\int_{1}^{\infty} x^{2} dx\). Here, the limits of integration are 1 and infinity (\infty), and the function to be integrated \(f(x) = x^{2}\).
02

Determine if the integral is improper

An integral is improper if either the interval of integration is infinite, or the function to be integrated approaches infinity at one or more points in the interval of integration. In this case, the interval of integration is from 1 to infinity, which is an infinite interval. Therefore, this is an improper integral.

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Most popular questions from this chapter

Use the Trapezoidal Rule and Simpson's Rule to approximate the value of the definite integral for the indicated value of \(n\). Compare these results with the exact value of the definite integral. Round your answers to four decimal places. $$ \int_{0}^{2} x^{3} d x, n=8 $$

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Use the Trapezoidal Rule and Simpson's Rule to approximate the value of the definite integral for the indicated value of \(n\). Compare these results with the exact value of the definite integral. Round your answers to four decimal places. \int_{0}^{2} x^{2} d x, n=4

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