Chapter 12: Problem 31
Find the indefinite integral. (Hint: Integration by parts is not required for all the integrals.) $$ \int \frac{\ln x}{x^{2}} d x $$
Short Answer
Expert verified
The indefinite integral of the function \(\frac{\ln x}{x^{2}}\) dx is -ln(x) - x + c.
Step by step solution
01
- Identifying the formula
We will use the formula for integration by parts which is: \[ \int udv = uv - \int v du \] where u is the function we wish to integrate and dv is the function which we can easily integrate. In this case, we will set: (1) \(u = ln(x)\), therefore, \(du = \(\frac{1}{x}\)dx\) (2) \(dv = \rac{1}{x^2} dx\), therefore, \(v = -\frac{1}{x} \)
02
- Applying the formula
Substituting u, du, v and dv in the integration by parts formula, we get: \[\int udv = uv - \int v du = (ln(x) * -\frac{1}{x}) - \int (-\frac{1}{x} * \frac{1}{x} dx)\] which simplifies to: \[-ln(x) + \int \frac{1}{x^2} dx\].
03
- Final Simplification
We now integrate and simplify the equation fully: \[-ln(x) + \int \frac{1}{x^2} dx = -ln(x) - x + c \], where c is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration by Parts
To solve certain integrals, mathematicians often rely on a technique called Integration by Parts. It's like breaking an intricate puzzle into manageable pieces. What we're essentially doing is rearranging the problem to make it easier to solve. The formula for integration by parts is:\[ \int u \, dv = uv - \int v \, du \]This formula is derived from the product rule of differentiation, but we apply it in reverse, or rather for integration here. Here's how you might approach a problem using this technique:
- Identify the parts of the integral that will be \( u \) and \( dv \). This choice is crucial for simplifying the integration process later.
- Once \( u \) and \( dv \) are chosen, find \( du \) by differentiating \( u \), and find \( v \) by integrating \( dv \).
- Substitute \( u \), \( dv \), \( du \), and \( v \) back into the integration by parts formula.
- Solve the remaining integral and simplify your equation.
Logarithmic Functions
Logarithmic functions, represented with \( \ln(x) \) in mathematics as the natural logarithm, are special because they are the inverse operations of exponentials. When dealing with integration and differentiation, understanding the behavior of logarithmic functions becomes crucial.
- The derivative of \( \ln(x) \) is \( \frac{1}{x} \), which makes integration involving logarithmic functions particularly interesting.
- Logarithmic rules can help simplify expressions, making them easier to integrate or differentiate.
Constant of Integration
In integral calculus, the Constant of Integration is essential when discussing indefinite integrals. It's a representation of all the possible constants that can be added to a function, all of which are solutions to the derivative problem.
- When you calculate an indefinite integral, it's not just one function you're finding; it's an entire family of functions. Each differs by this constant \( c \).
- The reason we include the constant \( c \) is because differentiation eliminates constants in the process, leaving us with an unknown that must be represented in the antiderivative.