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In Exercises, use the properties of logarithms to write the expression as a sum, difference, or multiple of logarithms. $$ \ln \left(x \sqrt[3]{x^{2}+1}\right) $$

Short Answer

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\ln (x) + \frac{1}{3} \ln (x^{2}+1)

Step by step solution

01

Apply Product Rule

Use the product rule of logarithms which states that \(\ln(ab) = \ln(a) + \ln(b)\). Here, \(a=x\) and \(b=\sqrt[3]{x^{2}+1}\). So, the given expression becomes \(\ln (x) + \ln (\sqrt[3]{x^{2}+1})\).
02

Apply Power Rule

Next, use the power rule of logarithms which states \(\ln(a^{n}) = n \cdot \ln(a)\). Here, \(a=x^{2}+1\) and \(n=1/3\) for the second term. So, it simplifies to \(\ln (x) + \frac{1}{3} \ln (x^{2}+1) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Product Rule
When working with logarithms, combining and simplifying expressions is a fundamental skill. One of the primary tools for this is the logarithm product rule, which helps break down the logs of products into simpler parts. This rule states that the log of a product is equal to the sum of the logs of its factors. Mathematically, this can be represented as \( \text{log}_b(mn) = \text{log}_b(m) + \text{log}_b(n) \).

For example, if we have \( \text{log}_2(3 \times 4) \), using the product rule it becomes \( \text{log}_2(3) + \text{log}_2(4) \). This property proves incredibly useful when dealing with expressions involving products within a logarithm, as it makes them simpler to handle and solve.
Logarithm Power Rule
Similarly essential in the toolbox for simplifying logarithmic expressions is the logarithm power rule. This rule comes into play when you're working with expressions where a logarithm is taken to a power. According to this rule, you can move the exponent of the argument to the front of the log expression as a multiplier. The formula is written as \( \text{log}_b(a^n) = n \times \text{log}_b(a) \).

Imagine dealing with \( \text{log}_3(9^2) \). By the power rule, you can change it to \( 2 \times \text{log}_3(9) \), which simplifies the expression. It's particularly useful for simplifying and solving equations that include terms raised to a power within a logarithm.
Natural Logarithms
Diving into specific types of logarithms, natural logarithms are a special category denoted by \( \text{ln}(x) \) and are based on the natural constant \( e \), approximately equal to 2.718. The natural logarithm of a number is the power to which \( e \) must be raised to obtain that number. For example, if \( e^y = x \), then \( \text{ln}(x) = y \).

Natural logarithms are particularly important in higher mathematics and appear in various applications across physics, engineering, and economics. They are the inverse operation of taking \( e \) to a power, and hence, they play a crucial role in solving exponential growth problems and finding time constants in decay processes.
Simplifying Logarithmic Expressions
When faced with complex logarithmic expressions, the ultimate goal is to simplify them into a form that's more manageable. This process often involves utilizing the product rule, power rule, and other properties of logarithms. The ability to simplify effectively allows for easier computation, comparison, and in many cases, can reveal the underlying patterns or solutions within logarithmic equations.

A simplification task might be transforming a single log with a complex argument into a series of logs added or subtracted from each other. Or it might be taking a compound expression and peeling away the layers by using these rules repeatedly. Simplifying is not only a skill but also an art that, when mastered, yields deep insight into the behavior of logarithmic functions and their characteristics in different mathematical scenarios.

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Most popular questions from this chapter

In Exercises, determine whether the statement is true or false given that \(f(x)=\ln x .\) If it is false, explain why or give an example that shows it is false. $$ f(x-2)=f(x)-f(2), \quad x>2 $$

The term \(t\) (in years) of a \(\$ 200,000\) home mortgage at \(7.5 \%\) interest can be approximated by \(t=-13.375 \ln \frac{x-1250}{x}, x>1250\) where \(x\) is the monthly payment in dollars. (a) Use a graphing utility to graph the model. (b) Use the model to approximate the term of a home mortgage for which the monthly payment is \(\$ 1398.43 .\) What is the total amount paid? (c) Use the model to approximate the term of a home mortgage for which the monthly payment is \(\$ 1611.19 .\) What is the total amount paid? (d) Find the instantaneous rate of change of \(t\) with respect to \(x\) when \(x=\$ 1398.43\) and \(x=\$ 1611.19\). (e) Write a short paragraph describing the benefit of the higher monthly payment.

The cumulative sales \(S\) (in thousands of units) of a new product after it has been on the market for \(t\) years are modeled by \(S=C e^{k / t}\) During the first year, 5000 units were sold. The saturation point for the market is 30,000 units. That is, the limit of \(S\) as \(t \rightarrow \infty\) is 30,000 . (a) Solve for \(C\) and \(k\) in the model. (b) How many units will be sold after 5 years? (c) Use a graphing utility to graph the sales function.

In Exercises, use a calculator to evaluate the logarithm. Round to three decimal places. $$ \log _{4} 7 $$

The effective yield is the annual rate \(i\) that will produce the same interest per year as the nominal rate \(r\) compounded \(n\) times per year. (a) For a rate \(r\) that is compounded \(n\) times per year, show that the effective yield is \(i=\left(1+\frac{r}{n}\right)^{n}-1 .\) (b) Find the effective yield for a nominal rate of \(6 \%\), compounded monthly.

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