Question

Solve for the indicated variable. Markup Solve for \(C\) in \(S=C+R C\)

Short answer

The value of \(C\) in the equation \(S=C+R C\) is \(C = \frac{S}{1+R}\).

Step-by-step solution

Combine like terms

Here, both \(C\) and \(R C\) are like terms. Write them together on one side. \(S = C(1 + R)\)

Isolate \(C\)

To get \(C\) on its own, we divide both sides of the equation by \((1 + R)\). This is done because dividing by \((1+R)\) on both sides helps us cancel out \(1+R\) from LHS. After dividing through by \(1 + R\), we get \(C = \frac{S}{1+R}\)

Key concepts

Algebraic Manipulation

The process of algebraic manipulation involves rearranging and simplifying mathematical expressions and equations to solve for a particular variable. It's like a puzzle where you apply various mathematical operations to achieve the desired result, all while adhering to the rules of algebra.

In the exercise given, we see an equation that initially seems complicated. The trick here is to understand that algebraic manipulation is about making these equations more workable by using operations such as addition, subtraction, multiplication, division, and sometimes factoring.

This process not only requires an understanding of basic arithmetic but also a grasp of the distributive, associative, and commutative properties of algebra. These properties allow us to reorder and regroup terms in a way that can simplify complex equations. For instance, in the equation provided, algebraic manipulation is used to combine like terms involving the variable C, and to factor out C, so that it becomes more straightforward to isolate and solve for.

Isolating Variables

The concept of isolating the variable is a fundamental aspect of solving equations. It means to rearrange the equation so that the variable you are solving for is by itself on one side of the equation, and all other terms are on the opposite side.

To isolate the variable, you might need to perform a series of operations that 'undo' what has been done to the variable. This often involves reverse operations— for example, if a variable is multiplied by a number, you would divide by that number to isolate it.

In the example at hand, the variable C, which we are solving for, is initially tied up in multiplication with (1+R). To isolate C, we divide both sides of the equation by (1+R). This technique effectively removes (1+R) and leaves C on its own on one side of the equal sign, giving us the solution in the form of C equals a certain quantity.

Combining Like Terms

When faced with algebraic expressions, one of the first steps towards simplification is combining like terms. Like terms are terms that have the exact same variable components raised to the same powers. In other words, they're identical in their variables, though they may have different coefficients.

By combining like terms, we reduce the complexity of the expression, making it easier to manipulate and leading us closer to a solution. Typically, this involves adding or subtracting coefficients of like terms while keeping the variable part unchanged.

In the textbook exercise, 'C' and 'RC' are considered like terms since they both contain the variable 'C'. By factoring out 'C' from these terms, we group them together into a single term 'C(1+R)', thus simplifying the equation substantially. This step is crucial because it sets us up to easily isolate 'C', which is our goal in solving the equation.