Dealing with fractions in algebra can sometimes be a challenge, but there is a straightforward technique to simplify such matters: clearing fractions from equations. This process involves eliminating all fractions so that you're left with a simpler, equivalent equation.
To clear fractions, find the least common denominator (LCD) of all the fractions present in the equation and multiply each term of the equation by this number. In the context of the exercise \frac{15}{x}-4=\frac{6}{x}+3\, the LCD is \(x\), since that’s the only denominator in the equation. By multiplying every term by \(x\), we effectively remove fractions:
- \((\frac{15}{x})\times x = 15\)
- \(- 4\times x = - 4x\)
- \((\frac{6}{x})\times x = 6\)
- \(3\times x = 3x\)
After multiplying, we're ready for the next phase: combining like terms and further solving the equation. This step simplifies the equation significantly, making it easier to isolate the variable and find the solution.