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Use a calculator to solve the quadratic equation. (Round your answer to three decimal places.) $$ -0.003 x^{2}+0.025 x-0.98=0 $$

Short Answer

Expert verified
The rounded solutions for x are \(x_1 = 8.968\) and \(x_2 = 36.367\)

Step by step solution

01

Identify the coefficients

Recognize and write down the coefficients. Here \(a = -0.003\), \(b = 0.025\) and \(c = -0.98\)
02

Substitute into the quadratic formula

Substitute the values of \(a\), \(b\) and \(c\) into the quadratic formula as follows: \(x = \frac{-0.025 \pm \sqrt{(0.025)^2 - 4*(-0.003)*-0.98}}{2*-0.003}\)
03

Computing the Discriminant

Compute the value inside the square root (the discriminant) first: \(D = (0.025)^2 - 4*(-0.003)*-0.98 = 0.000625 + 0.01176 = 0.012385\)
04

Solve for x

Now, compute the two possible solutions using the discriminant: \( x_1 = \frac{-0.025 - \sqrt{0.012385}}{2*-0.003} \) and \( x_2 = \frac{-0.025 + \sqrt{0.012385}}{2*-0.003} \)
05

Round the answers

In the final step, round the answers to three decimal places, using a calculator.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Formula
The quadratic formula is a fundamental tool for solving quadratic equations in the form \(ax^2 + bx + c = 0\). It provides an easy path to finding the roots or solutions of any quadratic equation. The quadratic formula is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Here, \(a\), \(b\), and \(c\) are the coefficients of the equation, where \(a eq 0\). The ± symbol indicates that there are usually two possible values for \(x\), giving two solutions for the equation. This formula is especially useful for equations where factoring is cumbersome or impossible.To use the quadratic formula successfully:
  • Identify and write down the values of \(a\), \(b\), and \(c\).
  • Plug these values into the formula.
  • Simplify carefully, keeping an eye on the signs and the arithmetic involved.
  • Remember to evaluate both possible answers using the ±.
Understanding and practicing the quadratic formula is crucial for solving various types of quadratic equations with ease.
Solving Equations
Solving quadratic equations involves finding the values of \(x\) that make the equation true. It usually results in two possible solutions. There are several methods for solving quadratic equations, but here we focus on using the quadratic formula.The process involves several key steps:
  • Identify the coefficients: Determine \(a\), \(b\), and \(c\) from the quadratic equation.
  • Substitute values into the quadratic formula: Substitute these coefficients into the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
  • Calculate the discriminant: First solve for the discriminant \(b^2 - 4ac\), which determines the nature of the roots.
  • Compute solutions: Insert the discriminant value into the formula and calculate both possible solutions for \(x\).
Most quadratic equations have two solutions, and using the quadratic formula helps find these solutions precisely. Practicing these steps with different equations will build confidence and proficiency.
Discriminant in Quadratic Equations
The discriminant is a part of the quadratic formula under the square root, given by \(D = b^2 - 4ac\). It plays a crucial role in determining the nature of the roots of the quadratic equation.Here's what the discriminant tells us:
  • Positive Discriminant (\(D > 0\)): There are two distinct real solutions.
  • Zero Discriminant (\(D = 0\)): There is one real solution, which is repeated. The parabola touches the x-axis at a single point.
  • Negative Discriminant (\(D < 0\)): There are no real solutions. Instead, there are two complex solutions, and the parabola does not intersect the x-axis.
In the provided exercise, calculating the discriminant was essential in identifying that the equation has two distinct real solutions. Understanding the discriminant helps in quickly assessing what type of solutions to expect, guiding your approach to solving the equation.

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Most popular questions from this chapter

The daily amount \(I\) (in thousands of barrels) of crude oil imported to the United States from 1995 to 2005 can be modeled by \(I=428.2 t+6976, \quad 5 \leq t \leq 15\) where \(t\) represents the year, with \(t=5\) corresponding to 1995. (a) Use the model to find the year in which the amount of crude oil imported to the United States exceeded 12 million barrels a day. (b) Use the model to predict the year in which the amount of oil imported to the United States will exceed 14 million barrels a day.

The revenue \(R\) and cost \(C\) for a product are given by \(R=x(75-0.0005 x)\) and \(C=30 x+250,000\), where \(R\) and \(C\) are measured in dollars and \(x\) represents the number of units sold (see figure). (a) How many units must be sold to obtain a profit of at least \(\$ 750,000 ?\) (b) The demand equation for the product is \(p=75-0.0005 x\) where \(p\) is the price per unit. What prices will produce a profit of at least \(\$ 750,000 ?\) (c) As the number of units increases, the revenue eventually decreases. After this point, at what number of units is the revenue approximately equal to the cost? How should this affect the company's decision about the level of production?

Solve the inequality and write the solution set in interval notation. \(4 x^{3}-x^{4} \geq 0\)

Use a calculator to solve the inequality. (Round each number in your answer to two decimal places.) \(0.4 x^{2}+5.26<10.2\)

The cost of renting a midsize car from Company A is \(\$ 279\) per week with no extra charge for mileage. The cost of renting a similar car from Company B is \(\$ 199\) per week, plus 32 cents for each mile driven. How many miles must you drive in a week to make the rental fee for Company \(\mathrm{B}\) greater than that for Company \(\mathrm{A}\) ?

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