Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Exercises 1-8, use the discriminant to determine the number of real solutions of the quadratic equation. \(4 x^{2}-4 x+1=0\)

Short Answer

Expert verified
The quadratic equation \(4x^2 - 4x + 1 = 0\) has exactly one real solution.

Step by step solution

01

Identify the coefficients

First, identify the coefficients of the quadratic equation \(4x^2 - 4x + 1 = 0\). Here, \(a = 4\), \(b = -4\), and \(c = 1\).
02

Calculate the Discriminant

Next, calculate the discriminant \(D\), which is given by the formula \(D = b^2 - 4ac\). Substituting the identified coefficients: \(D = (-4)^2 - 4*4*1 = 16 - 16 = 0\).
03

Determine the number of real solutions

Finally, determine the number of real solutions. Since the discriminant \(D = 0\), the quadratic equation has exactly one real solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Real Solutions of Quadratic Equations
Understanding the nature of solutions to quadratic equations is crucial for various mathematical applications. Quadratic equations are often in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(x\) represents the unknown. The solutions to these equations can be real or complex numbers.

When we talk about real solutions, we mean the values of \(x\) that are not accompanied by the imaginary unit \(i\). The number of real solutions depends directly on the value of the discriminant, which we'll discuss in the following sections. A positive discriminant indicates two distinct real solutions, a zero discriminant points to exactly one real solution (also known as a repeated or double root), and a negative discriminant tells us that there are no real solutions, just complex ones.
Calculating Discriminant
The discriminant is a powerful tool used to determine the nature and number of solutions of a quadratic equation without actually solving the equation. The discriminant, often denoted as \(D\), is part of the quadratic formula and can be computed using the coefficients \(a\), \(b\), and \(c\) of the quadratic equation.

It is calculated with the formula \(D = b^2 - 4ac\). The outcome of this calculation will dictate whether the quadratic equation has two real solutions (if \(D > 0\)), one real solution (if \(D = 0\)), or two complex solutions (if \(D < 0\)). For example, with an equation \(4x^2 - 4x + 1 = 0\), using the coefficients, the discriminant would be \(D = (-4)^2 - 4(4)(1)\), which simplifies to \(D = 0\). This tells us there is exactly one real solution.

Discriminant Case Study

  • If \(D > 0\), there are two real and distinct solutions.
  • If \(D = 0\), there is one real and repeated solution.
  • If \(D < 0\), there are no real solutions, only two complex ones.
Quadratic Formula
The quadratic formula is perhaps the most recognized tool for solving quadratic equations and it directly incorporates the discriminant. This formula provides the solutions for \(x\) in any quadratic equation \(ax^2 + bx + c = 0\): \(x = \frac{-b \pm \sqrt{D}}{2a}\), where \(\pm\) signifies that there are usually two solutions, depending on the sign chosen.

Applying this formula involves inserting the identified coefficients and the computed discriminant. Going back to our example, \(4x^2 - 4x + 1 = 0\), we found that \(D = 0\). Using the quadratic formula with our coefficients and this discriminant gives us the real solution: \(x = \frac{-(-4) \pm \sqrt{0}}{2(4)} = 1\), confirming that there is one real solution at \(x = 1\).

Application of the Quadratic Formula

  • It systematically solves any quadratic equation.
  • Regardless of the discriminant's value, the formula applies: positive, zero, or negative.
  • It reveals the actual solutions after determining the nature of the solutions via the discriminant.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A doughnut shop sells a dozen doughnuts for \(\$ 3.95 .\) Beyond the fixed costs (rent, utilities, and insurance) of \(\$ 165\) per day, it costs \(\$ 1.45\) for enough materials (flour, sugar, and so on) and labor to produce a dozen doughnuts. The daily profit from doughnut sales varies between \(\$ 100\) and \(\$ 400\). Between what numbers of doughnuts (in dozens) do the daily sales vary?

The average yearly cost \(C\) of higher education at private institutions in the United States for the academic years \(1995 / 1996\) to \(2004 / 2005\) can be modeled by \(C=42.93 t^{2}+68.0 t+15,309, \quad 6 \leq t \leq 15\) where \(t\) represents the year, with \(t=6\) corresponding to the academic year \(1995 / 1996\) (see figure). Use the model to predict the academic year in which the average yearly cost of higher education at private institutions exceeds \(\$ 32,000\).

The average yearly cost \(C\) of higher education at public institutions in the United States for the academic years \(1995 / 1996\) to \(2004 / 2005\) can be modeled by \(C=30.57 t^{2}-259.6 t+6828, \quad 6 \leq t \leq 15\) where \(t\) represents the year, with \(t=6\) corresponding to the \(1995 / 1996\) school year (see figure). Use the model to predict the academic year in which the average yearly cost of higher education at public institutions exceeds \(\$ 12,000\).

Solve the inequality. Then graph the solution set on the real number line. \(\frac{3}{2} x \geq 9\)

Find the domain of the expression. \(\sqrt{x^{2}-9}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free